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Two $q$-analogues of Euler's formula $\zeta(2)=\pi^2/6$

Number Theory 2019-11-20 v6 Combinatorics

Abstract

It is well known that ζ(2)=π2/6\zeta(2)=\pi^2/6 as discovered by Euler. In this paper we present the following two qq-analogues of this celebrated formula: k=0qk(1+q2k+1)(1q2k+1)2=n=1(1q2n)4(1q2n1)4\sum_{k=0}^\infty\frac{q^k(1+q^{2k+1})}{(1-q^{2k+1})^2}=\prod_{n=1}^\infty\frac{(1-q^{2n})^4}{(1-q^{2n-1})^4} and k=0q2k(1)kk/2(1q2k+1)2=n=1(1q2n)2(1q4n)2(1q2n1)2(1q4n2)2,\sum_{k=0}^\infty\frac{q^{2k-\lfloor(-1)^kk/2\rfloor}}{(1-q^{2k+1})^2} =\prod_{n=1}^\infty\frac{(1-q^{2n})^2(1-q^{4n})^2}{(1-q^{2n-1})^2(1-q^{4n-2})^2}, where qq is any complex number with q<1|q|<1. We also give a qq-analogue of the identity ζ(4)=π4/90\zeta(4)=\pi^4/90, and pose a problem on qq-analogues of Euler's formula for ζ(2m) (m=3,4,)\zeta(2m)\ (m=3,4,\ldots).

Keywords

Cite

@article{arxiv.1802.01473,
  title  = {Two $q$-analogues of Euler's formula $\zeta(2)=\pi^2/6$},
  author = {Zhi-Wei Sun},
  journal= {arXiv preprint arXiv:1802.01473},
  year   = {2019}
}

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8 pages