English

Totalseparierte Moduln

Commutative Algebra 2015-04-02 v1 Rings and Algebras

Abstract

Let (R,m)(R, \mathfrak{m}) be a noetherian local ring, MM a separated RR-module (i.e. n1mnM=0\bigcap\limits_{n\geq 1}\mathfrak{m}^n M = 0) and M^=limM/mnM\widehat{M} = \lim\limits_{\leftarrow} M/\mathfrak{m}^n M its completion. Generally, MM is not pure in M^\widehat{M} and M^\widehat{M} is not pure-injective. But if MM is totally separated, i.e. XRMX\underset{R}{\otimes} M is separated for all finitely generated RR-modules XX, the situation improves: In this case, MM is pure in M^\widehat{M} and, under additional conditions, M^\widehat{M} is even pure-injective, e.g. if MX(I)M\cong X^{(I)} holds with XX finitely generated or Mi=1R/miM \cong\coprod_{i=1}^{\infty} R/\mathfrak{m}^i. In section 2, we investigate the question under which conditions both MM and M^\widehat{M} are totally separated and establish a close connection to the class of strictly pure-essential extensions. In section 3, we replace the completion M^\widehat{M} in the case M=iIMiM = \coprod_{i\in I}M_i with the m\mathfrak{m}-adic closure AA of MM in P=iIMiP = \prod_{i\in I} M_i, i.e. with A=n1(M+mnP)A = \bigcap_{n \geq 1}(M + \mathfrak{m}^n P). We give criteria so that A/MA/M is radical and show that this always holds in the countable case M=i=1MiM = \coprod_{i=1}^{\infty} M_i. Finally, we deal with the case that AA is even totally separated and additionally determine the coassociated prime ideals of A/MA/M.

Keywords

Cite

@article{arxiv.1504.00168,
  title  = {Totalseparierte Moduln},
  author = {Helmut Zöschinger},
  journal= {arXiv preprint arXiv:1504.00168},
  year   = {2015}
}

Comments

12 pages, in German

R2 v1 2026-06-22T09:07:49.267Z