The Pythagoras number of fields of transcendence degree $1$ over $\mathbb{Q}$
Algebraic Geometry
2025-07-08 v2 Number Theory
Abstract
We show that any sum of squares in a field of transcendence degree over is a sum of squares, answering a question of Pop and Pfister. We deduce this result from a representation theorem, in , for quadratic forms of rank with coefficients in , where is a curve over a number field .
Cite
@article{arxiv.2506.21380,
title = {The Pythagoras number of fields of transcendence degree $1$ over $\mathbb{Q}$},
author = {Olivier Benoist},
journal= {arXiv preprint arXiv:2506.21380},
year = {2025}
}
Comments
23 pages, minor modifications