English

Pythagoras number of quartic orders containing $\sqrt{2}$

Number Theory 2025-07-24 v3

Abstract

Let KK be a quartic number field containing 2\sqrt{2} and let OK\mathcal{O}\subseteq K be an order such that 2O\sqrt{2}\in \mathcal{O}. We prove that the Pythagoras number of O\mathcal{O} is at most 5. This confirms a conjecture of Kr\'{a}sensk\'{y}, Ra\v{s}ka and Sgallov\'a. The proof makes use of Beli's theory of bases of norm generators for quadratic lattices over dyadic local fields.

Keywords

Cite

@article{arxiv.2204.10468,
  title  = {Pythagoras number of quartic orders containing $\sqrt{2}$},
  author = {Zilong He and Yong Hu},
  journal= {arXiv preprint arXiv:2204.10468},
  year   = {2025}
}

Comments

v3: numbering system changed to be consistent with the published version. Chinese version published in Chinese Ann. Math. Ser. A 45 (2024), no. 3, 287--296.; English translation in Chinese Journal of Contemporary Mathematics, 45 (2024) no. 3

R2 v1 2026-06-24T10:55:27.030Z