English

The dimensional Brunn-Minkowski inequality in Gauss space

Metric Geometry 2020-04-30 v2 Functional Analysis

Abstract

Let γn\gamma_n be the standard Gaussian measure on Rn\mathbb{R}^n. We prove that for every symmetric convex sets K,LK,L in Rn\mathbb{R}^n and every λ(0,1)\lambda\in(0,1), γn(λK+(1λ)L)1nλγn(K)1n+(1λ)γn(L)1n,\gamma_n(\lambda K+(1-\lambda)L)^{\frac{1}{n}} \geq \lambda \gamma_n(K)^{\frac{1}{n}}+(1-\lambda)\gamma_n(L)^{\frac{1}{n}}, thus settling a problem raised by Gardner and Zvavitch (2010). This is the Gaussian analogue of the classical Brunn-Minkowski inequality for the Lebesgue measure. We also show that, for a fixed λ(0,1)\lambda\in(0,1), equality is attained if and only if K=LK=L.

Keywords

Cite

@article{arxiv.2004.07146,
  title  = {The dimensional Brunn-Minkowski inequality in Gauss space},
  author = {Alexandros Eskenazis and Georgios Moschidis},
  journal= {arXiv preprint arXiv:2004.07146},
  year   = {2020}
}