English

Some results on vanishing coefficients in infinite product expansions

Number Theory 2023-01-30 v1

Abstract

Recently, M. D. Hirschhorn proved that, if n=0anqn:=(q,q4;q5)(q,q9;q10)3\sum_{n=0}^\infty a_nq^n := (-q,-q^4;q^5)_\infty(q,q^9;q^{10})_\infty^3 and n=0bnqn:=(q2,q3;q5)(q3,q7;q10)3\sum_{n=0}^\infty b_nq^n:=(-q^2,-q^3;q^5)_\infty(q^3,q^7;q^{10})_\infty^3, then a5n+2=a5n+4=0a_{5n+2}=a_{5n+4}=0 and b5n+1=b5n+4=0b_{5n+1}=b_{5n+4}=0. Motivated by the work of Hirschhorn, D. Tang proved some comparable results including the following: If n=0cnqn:=(q,q4;q5)3(q3,q7;q10) \sum_{n=0}^\infty c_nq^n := (-q,-q^4;q^5)_\infty^3(q^3,q^7;q^{10})_\infty and n=0dnqn:=(q2,q3;q5)3(q,q9;q10)\sum_{n=0}^\infty d_nq^n := (-q^2,-q^3;q^5)_\infty^3(q,q^9;q^{10})_\infty, then c5n+3=c5n+4=0c_{5n+3}=c_{5n+4}=0 and d5n+3=d5n+4=0d_{5n+3}=d_{5n+4}=0. In this paper, we prove that a5n=b5n+2a_{5n}=b_{5n+2}, a5n+1=b5n+3a_{5n+1}=b_{5n+3}, a5n+2=b5n+4a_{5n+2}=b_{5n+4}, a5n1=b5n+1a_{5n-1}=b_{5n+1}, c5n+3=d5n+3c_{5n+3}=d_{5n+3}, c5n+4=d5n+4c_{5n+4}=d_{5n+4}, c5n=d5nc_{5n}=d_{5n}, c5n+2=d5n+2c_{5n+2}=d_{5n+2}, and c5n+1>d5n+1c_{5n+1}>d_{5n+1}. We also record some other comparable results not listed by Tang.

Keywords

Cite

@article{arxiv.1908.07737,
  title  = {Some results on vanishing coefficients in infinite product expansions},
  author = {Nayandeep Deka Baruah and Mandeep Kaur},
  journal= {arXiv preprint arXiv:1908.07737},
  year   = {2023}
}

Comments

15 pages