English

Semi-Invariant Subrings

Rings and Algebras 2015-04-07 v2

Abstract

We say that a subring R0R_0 of a ring RR is semi-invariant if R0R_0 is the ring of invariants in RR under some set of ring endomorphisms of some ring containing RR. We show that R0R_0 is semi-invariant if and only if there is a ring SRS\supseteq R and a set XSX\subseteq S such that R0=\CentR(X):=rR\suchthatxr=rxxXR_0=\Cent_R(X):={r\in R \suchthat xr=rx \forall x\in X}; in particular, centralizers of subsets of RR are semi-invariant subrings. We prove various properties of semi-invariant subrings and show how they can be used for various applications including: (1) The center of a semiprimary (resp. right perfect) ring is semiprimary (resp. right perfect). (2) If MM is a finitely presented module over a "good" semiperfect ring (e.g. an inverse limit of semiprimary rings), then (M)(M) is semiperfect, hence MM has a Krull-Schmidt decomposition. (This generalizes results of Bjork and Rowen). (3) If ρ\rho is a representation of a monoid or a ring over a module with a "good" semiperfect endomorphism ring (in the sense of (2)), then ρ\rho has a Krull-Schmidt decomposition. (4) If SS is a "good" commutative semiperfect ring and RR is an SS-algebra that is f.p.\ as an SS-module, then RR is semiperfect. (5) Let RSR\subseteq S be rings and let MM be a right SS-module. If (MR)(M_R) is semiprimary (resp. right perfect), then (MS)(M_S) is semiprimary (resp. right perfect).

Keywords

Cite

@article{arxiv.1212.2124,
  title  = {Semi-Invariant Subrings},
  author = {Uriya A. First},
  journal= {arXiv preprint arXiv:1212.2124},
  year   = {2015}
}

Comments

31 pages

R2 v1 2026-06-21T22:51:41.822Z