English

Rooted induced trees in triangle-free graphs

Combinatorics 2008-12-15 v2

Abstract

For a graph GG, let t(G)t(G) denote the maximum number of vertices in an induced subgraph of GG that is a tree. Further, for a vertex vV(G)v\in V(G), let tv(G)t^v(G) denote the maximum number of vertices in an induced subgraph of GG that is a tree, with the extra condition that the tree must contain vv. The minimum of t(G)t(G) (tv(G)t^v(G), respectively) over all connected triangle-free graphs GG (and vertices vV(G)v\in V(G)) on nn vertices is denoted by t3(n)t_3(n) (t3v(n)t_3^v(n)). Clearly, tv(G)t(G)t^v(G)\le t(G) for all vV(G)v\in V(G). In this note, we solve the extremal problem of maximizing G|G| for given tv(G)t^v(G), given that GG is connected and triangle-free. We show that G1+(tv(G)1)tv(G)2|G|\le 1+\frac{(t_v(G)-1)t_v(G)}{2} and determine the unique extremal graphs. Thus, we get as corollary that t3(n)t3v(n)=1/2(1+8n7)t_3(n)\ge t_3^v(n)=\lceil {1/2}(1+\sqrt{8n-7})\rceil, improving a recent result by Fox, Loh and Sudakov.

Keywords

Cite

@article{arxiv.0804.1535,
  title  = {Rooted induced trees in triangle-free graphs},
  author = {Florian Pfender},
  journal= {arXiv preprint arXiv:0804.1535},
  year   = {2008}
}

Comments

2 pages, minor edits for better readability

R2 v1 2026-06-21T10:29:20.030Z