English

Proof of a conjectural supercongruence modulo $p^5$

Number Theory 2021-09-22 v1

Abstract

In this paper we prove the supercongruence n=0(p1)/26n+1256n(2nn)3p(1)(p1)/2+(1)(p1)/2724p4Bp3(modp5)\sum_{n=0}^{(p-1)/2}\frac{6n+1}{256^n}\binom{2n}n^3\equiv p(-1)^{(p-1)/2}+(-1)^{(p-1)/2}\frac{7}{24}p^4B_{p-3}\pmod{p^5} for any prime p>3p>3, which was conjectured by Sun in 2019.

Keywords

Cite

@article{arxiv.2109.09877,
  title  = {Proof of a conjectural supercongruence modulo $p^5$},
  author = {Guo-Shuai Mao and Zhi-Wei Sun},
  journal= {arXiv preprint arXiv:2109.09877},
  year   = {2021}
}
R2 v1 2026-06-24T06:09:48.697Z