English

Poset Ramsey numbers: large Boolean lattice versus a fixed poset

Combinatorics 2021-10-18 v1

Abstract

Given partially ordered sets (posets) (P,P)(P, \leq_P) and (P,P)(P', \leq_{P'}), we say that PP' contains a copy of PP if for some injective function f:PPf: P\rightarrow P' and for any X,YPX, Y\in P, XPYX\leq _P Y if and only of f(X)Pf(Y)f(X)\leq_{P'} f(Y). For any posets PP and QQ, the poset Ramsey number R(P,Q)R(P,Q) is the least positive integer NN such that no matter how the elements of an NN-dimensional Boolean lattice are colored in blue and red, there is either a copy of PP with all blue elements or a copy of QQ with all red elements. We focus on a poset Ramsey number R(P,Qn)R(P, Q_n) for a fixed poset PP and an nn-dimensional Boolean lattice QnQ_n, as nn grows large. We show a sharp jump in behaviour of this number as a function of nn depending on whether or not PP contains a copy of either a poset VV, i.e. a poset on elements A,B,CA, B, C such that B>CB>C, A>CA>C, and AA and BB incomparable, or a poset Λ\Lambda, its symmetric counterpart. Specifically, we prove that if PP contains a copy of VV or Λ\Lambda then R(P,Qn)n+115nlognR(P, Q_n) \geq n +\frac{1}{15} \frac{n}{\log n}. Otherwise R(P,Qn)n+c(P)R(P, Q_n) \leq n + c(P) for a constant c(P)c(P). This gives the first non-marginal improvement of a lower bound on poset Ramsey numbers and as a consequence gives R(Q2,Qn)=n+Θ(nlogn)R(Q_2, Q_n) = n + \Theta (\frac{n}{\log n}).

Keywords

Cite

@article{arxiv.2110.07648,
  title  = {Poset Ramsey numbers: large Boolean lattice versus a fixed poset},
  author = {Maria Axenovich and Christian Winter},
  journal= {arXiv preprint arXiv:2110.07648},
  year   = {2021}
}

Comments

18 pages, 2 figures

R2 v1 2026-06-24T06:53:59.312Z