English

On the Minimum Width of a Cutset in the Truncated Boolean Lattice

Combinatorics 2015-12-10 v1

Abstract

For integers 0mlnm0 \leq m \leq l \leq n-m, the truncated Boolean lattice Bn(m,l){\cal B}_n(m,l) is the poset of all subsets of [n]={1,2,,n}[n] = \{1, 2, \ldots, n\} which have size at least mm and at most ll. CBn(m,l){\cal C} \subseteq {\cal B}_n(m,l) is a {\em cutset} if it meets every chain of length lml-m in Bn(m,l){\cal B}_n(m,l), and the {\em width} of C{\cal C} is the size of the largest antichain in C{\cal C}. We conjecture that for n>>mn >> m the minimum width hn(m,l)h_n(m,l) of a cutset in Bn(m,l){\cal B}_n(m,l) is Σj0Δn(mjc)=Δn(m)+Δn(mc)+Δn(m2c)+\Sigma_{j \geq 0} \Delta_n(m-jc) = \Delta_n(m)+\Delta_n(m-c)+\Delta_n(m-2c)+ \dots, where c=lm+1c=l-m+1 is the number of level sets in Bn(m,l){\cal B}_n(m,l) and Δn(k)=(nk)(nk1)\Delta_n(k)={n \choose k}- {n \choose k-1}. We establish our conjecture for the cases of "short lattices" (l=ml=m, l=m+1l=m+1, and l=m+2l=m+2). For "taller lattices" (l2ml \geq 2m) our conjecture gives (nm)(nm1){n \choose m} - {n \choose m-1}, independently of ll. Our main result is that hn(m,l)(nm)(nm1)h_n(m,l) \leq {n \choose m} - {n \choose m-1} if l2ml \geq 2m.

Keywords

Cite

@article{arxiv.1512.02978,
  title  = {On the Minimum Width of a Cutset in the Truncated Boolean Lattice},
  author = {Béla Bajnok},
  journal= {arXiv preprint arXiv:1512.02978},
  year   = {2015}
}