English

On the geometric mean of the first n primes

Number Theory 2016-03-03 v1

Abstract

Let pnp_n be the nnth prime, and consider the sequence sn=(23pn)1/n=(pn#)1/ns_n = (2\cdot3\cdots p_n)^{1/n} = (p_n\#)^{1/n}, the geometric mean of the first nn primes. We give a short proof that pn/snep_n/s_n \to e, a result conjectured by Vrba (2010) and proved by Sandor and Verroken (2011). We show that pn/sn=exp(1+1/logpn+O(1/log2pn))p_n/s_n = \exp(1+1/\log p_n + O(1/\log^2 p_n)) as nn\to\infty, and give explicit lower and upper bounds for the O(1/log2pn)O(1/\log^2 p_n) term.

Keywords

Cite

@article{arxiv.1603.00855,
  title  = {On the geometric mean of the first n primes},
  author = {Alexei Kourbatov},
  journal= {arXiv preprint arXiv:1603.00855},
  year   = {2016}
}

Comments

4 pages, 1 table