English

On Hedetniemi's conjecture and the Poljak-Rodl function

Combinatorics 2019-12-06 v2

Abstract

Hedetniemi conjectured in 1966 that χ(G×H)=min{χ(G),χ(H)}\chi(G \times H) = \min\{\chi(G), \chi(H)\} for any graphs G and H. Here G×HG\times H is the graph with vertex set V(G)×V(H) V(G)\times V(H) defined by putting (x,y)(x,y) and (x,y)(x',y') adjacent if and only if xxE(G)xx'\in E(G) and yyV(H)yy'\in V(H). This conjecture received a lot of attention in the past half century. It was disproved recently by Shitov. The Poljak-R\"{o}dl function is defined as f(n)=min{χ(G×H):χ(G)=χ(H)=n}f(n) = \min\{\chi(G \times H): \chi(G)=\chi(H)=n\}. Hedetniemi's conjecture is equivalent to saying f(n)=nf(n)=n for all integer nn. Shitov's result shows that f(n)<nf(n)<n when nn is sufficiently large. Using Shitov's result, Tardif and Zhu showed that f(n)n(logn)1/4f(n) \le n - (\log n)^{1/4} for sufficiently large nn. Using Shitov's method, He--Wigderson showed that for ϵ109\epsilon \approx 10^{-9} and nn sufficiently large, f(n)(1ϵ)nf(n) \le (1-\epsilon)n. In this note we prove that a slight modification of the proof in the paper of Zhu and Tardif shows that f(n)(12+o(1))nf(n) \le (\frac 12 + o(1))n for sufficiently large nn. On the other hand, it is unknown whether f(n)f(n) is bounded by a constant. However, we do know that if f(n)f(n) is bounded by a constant, then the smallest such constant is at most 99. This lecture note gives self-contained proofs of the above mentioned results.

Cite

@article{arxiv.1911.12015,
  title  = {On Hedetniemi's conjecture and the Poljak-Rodl function},
  author = {Xuding Zhu},
  journal= {arXiv preprint arXiv:1911.12015},
  year   = {2019}
}

Comments

12 pages

R2 v1 2026-06-23T12:28:42.305Z