English

On Avoiding Sufficiently Long Abelian Squares

Combinatorics 2010-12-03 v1 Discrete Mathematics

Abstract

A finite word ww is an abelian square if w=xxw = xx^\prime with xx^\prime a permutation of xx. In 1972, Entringer, Jackson, and Schatz proved that every binary word of length k2+6kk^2 + 6k contains an abelian square of length 2k\geq 2k. We use Cartesian lattice paths to characterize abelian squares in binary sequences, and construct a binary word of length q(q+1)q(q+1) avoiding abelian squares of length 22q(q+1)\geq 2\sqrt{2q(q+1)} or greater. We thus prove that the length of the longest binary word avoiding abelian squares of length 2k2k is Θ(k2)\Theta(k^2).

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Cite

@article{arxiv.1012.0524,
  title  = {On Avoiding Sufficiently Long Abelian Squares},
  author = {Elyot Grant},
  journal= {arXiv preprint arXiv:1012.0524},
  year   = {2010}
}

Comments

5 pages

R2 v1 2026-06-21T16:52:37.742Z