English

$\mathbf{Bad}(s,t)$ is hyperplane absolute winning

Number Theory 2014-09-17 v2

Abstract

J. An (2013) proved that for any s,t0s,t \geq 0 such that s+t=1s + t = 1, Bad(s,t)\mathbf{Bad}(s,t) is (342)1(34\sqrt 2)^{-1}-winning for Schmidt's game. We show that using the main lemma from An's paper one can derive a stronger result, namely that Bad(s,t)\mathbf{Bad}(s,t) is hyperplane absolute winning in the sense of Broderick, Fishman, Kleinbock, Reich, and Weiss (2012). As a consequence one can deduce the full dimension of Bad(s,t)\mathbf{Bad}(s,t) intersected with certain fractals.

Cite

@article{arxiv.1307.5037,
  title  = {$\mathbf{Bad}(s,t)$ is hyperplane absolute winning},
  author = {Erez Nesharim and David S. Simmons},
  journal= {arXiv preprint arXiv:1307.5037},
  year   = {2014}
}
R2 v1 2026-06-22T00:53:57.095Z