English

How to prove that some Bernoulli convolution has the weak Gibbs property

Dynamical Systems 2014-12-31 v4 General Mathematics

Abstract

In this paper we give an example of uniform convergence of the sequence of column vectors A1AnVA1AnV\displaystyle{A_1\dots A_nV\over\left\Vert A_1\dots A_nV\right\Vert}, Ai{A,B,C}A_i\in\{A,B,C\}, A,B,CA,B,C being some (0,1)(0,1)-matrices of order 77 with much null entries, and VV a fixed positive column vector. These matrices come from the study of the Bernoulli convolution in the base β>1\beta>1 such that β3=2β2β+1\beta^3=2\beta^2-\beta+1, that is, the (continuous singular) probability distribution of the random variable (β1)n=1ωnβn\displaystyle(\beta-1)\sum_{n=1}^\infty{\omega_n\over\beta^n} when the independent random variables ωn\omega_n take the values 00 and 11 with probability 12\displaystyle{1\over2}. In the last section we deduce, from the uniform convergence of A1AnVA1AnV\displaystyle{A_1\dots A_nV\over\left\Vert A_1\dots A_nV\right\Vert}, the Gibbs and the multifractal properties of this measure.

Keywords

Cite

@article{arxiv.1006.3616,
  title  = {How to prove that some Bernoulli convolution has the weak Gibbs property},
  author = {Éric Olivier and Alain Thomas},
  journal= {arXiv preprint arXiv:1006.3616},
  year   = {2014}
}

Comments

We have included the content of this paper in arXiv:0908.4171

R2 v1 2026-06-21T15:38:00.360Z