English

Frustrated Triangles

Combinatorics 2015-04-10 v2

Abstract

A triple of vertices in a graph is a \emph{frustrated triangle} if it induces an odd number of edges. We study the set Fn[0,(n3)]F_n\subset[0,\binom{n}{3}] of possible number of frustrated triangles f(G)f(G) in a graph GG on nn vertices. We prove that about two thirds of the numbers in [0,n3/2][0,n^{3/2}] cannot appear in FnF_n, and we characterise the graphs GG with f(G)[0,n3/2]f(G)\in[0,n^{3/2}]. More precisely, our main result is that, for each n3n\geq 3, FnF_n contains two interlacing sequences 0=a0b0a1b1ambmn3/20=a_0\leq b_0\leq a_1\leq b_1\leq \dots \leq a_m\leq b_m\sim n^{3/2} such that Fn(bt,at+1)=F_n\cap(b_t,a_{t+1})=\emptyset for all tt, where the gaps are btat+1=(n2)t(t+1)|b_t-a_{t+1}|=(n-2)-t(t+1) and atbt=t(t1)|a_t-b_t|=t(t-1). Moreover, f(G)[at,bt]f(G)\in[a_t,b_t] if and only if GG can be obtained from a complete bipartite graph by flipping exactly tt edges/nonedges. On the other hand, we show, for all nn sufficiently large, that if m[f(n),(n3)f(n)]m\in[f(n),\binom{n}{3}-f(n)], then mFnm\in F_n where f(n)f(n) is asymptotically best possible with f(n)n3/2f(n)\sim n^{3/2} for nn even and f(n)2n3/2f(n)\sim \sqrt{2}n^{3/2} for nn odd. Furthermore, we determine the graphs with the minimum number of frustrated triangles amongst those with nn vertices and en2/4e\leq n^2/4 edges.

Keywords

Cite

@article{arxiv.1411.1749,
  title  = {Frustrated Triangles},
  author = {Teeradej Kittipassorn and Gabor Meszaros},
  journal= {arXiv preprint arXiv:1411.1749},
  year   = {2015}
}

Comments

19 pages, 4 figures, submitted

R2 v1 2026-06-22T06:50:33.553Z