Forbidding a Set Difference of Size 1
Combinatorics
2013-11-25 v2
Abstract
How large can a family \cal A \subset \cal P [n] be if it does not contain A,B with |A\setminus B| = 1? Our aim in this paper is to show that any such family has size at most \frac{2+o(1)}{n} \binom {n}{\lfloor n/2\rfloor }. This is tight up to a multiplicative constant of . We also obtain similar results for families \cal A \subset \cal P[n] with |A\setminus B| \neq k, showing that they satisfy |{\mathcal A}| \leq \frac{C_k}{n^k}\binom {n}{\lfloor n/2\rfloor }, where C_k is a constant depending only on k.
Cite
@article{arxiv.1304.7471,
title = {Forbidding a Set Difference of Size 1},
author = {Imre Leader and Eoin Long},
journal= {arXiv preprint arXiv:1304.7471},
year = {2013}
}
Comments
8 pages. Extended to include bound for families \cal A \subset \cal P [n] satisfying |A\setminus B| \neq k for all A,B \in \cal A