English

Faster sublinear approximations of $k$-cliques for low arboricity graphs

Data Structures and Algorithms 2018-11-13 v1

Abstract

Given query access to an undirected graph GG, we consider the problem of computing a (1±ϵ)(1\pm\epsilon)-approximation of the number of kk-cliques in GG. The standard query model for general graphs allows for degree queries, neighbor queries, and pair queries. Let nn be the number of vertices, mm be the number of edges, and nkn_k be the number of kk-cliques. Previous work by Eden, Ron and Seshadhri (STOC 2018) gives an O(nnk1/k+mk/2nk)O^*(\frac{n}{n^{1/k}_k} + \frac{m^{k/2}}{n_k})-time algorithm for this problem (we use O()O^*(\cdot) to suppress \poly(logn,1/ϵ,kk)\poly(\log n, 1/\epsilon, k^k) dependencies). Moreover, this bound is nearly optimal when the expression is sublinear in the size of the graph. Our motivation is to circumvent this lower bound, by parameterizing the complexity in terms of \emph{graph arboricity}. The arboricity of GG is a measure for the graph density "everywhere". We design an algorithm for the class of graphs with arboricity at most α\alpha, whose running time is O(min{nαk1nk,nnk1/k+mαk2nk})O^*(\min\{\frac{n\alpha^{k-1}}{n_k},\, \frac{n}{n_k^{1/k}}+\frac{m \alpha^{k-2}}{n_k} \}). We also prove a nearly matching lower bound. For all graphs, the arboricity is O(m)O(\sqrt m), so this bound subsumes all previous results on sublinear clique approximation. As a special case of interest, consider minor-closed families of graphs, which have constant arboricity. Our result implies that for any minor-closed family of graphs, there is a (1±ϵ)(1\pm\epsilon)-approximation algorithm for nkn_k that has running time O(nnk)O^*(\frac{n}{n_k}). Such a bound was not known even for the special (classic) case of triangle counting in planar graphs.

Keywords

Cite

@article{arxiv.1811.04425,
  title  = {Faster sublinear approximations of $k$-cliques for low arboricity graphs},
  author = {Talya Eden and Dana Ron and C. Seshadhri},
  journal= {arXiv preprint arXiv:1811.04425},
  year   = {2018}
}