English

Computational explorations of the Thompson group T for the amenability problem of F

Group Theory 2018-09-25 v3 Operator Algebras

Abstract

It is a long standing open problem whether the Thompson group FF is an amenable group. In this paper we show that if AA, BB, CC denote the standard generators of Thompson group TT and D:=CBA1D:=C B A^{-1} then 2+3<112(I+C+C2)(I+D+D2+D3)2+2.\sqrt2+\sqrt3\,<\,\frac1{\sqrt{12}}||(I+C+C^2)(I+D+D^2+D^3)||\,\le\, 2+\sqrt2. Moreover, the upper bound is attained if the Thompson group FF is amenable. Here, the norm of an element in the group ring CT\mathbb{C} T is computed in B(2(T))B(\ell^2(T)) via the regular representation of TT. Using the "cyclic reduced" numbers τ(((C+C2)(D+D2+D3))n)\tau(((C+C^2)(D+D^2+D^3))^n), nNn\in\mathbb{N}, and some methods from our previous paper [arXiv:1409.1486] we can obtain precise lower bounds as well as good estimates of the spectral distributions of 112((I+C+C2)(I+D+D2+D3))(I+C+C2)(I+D+D2+D3),\frac1{12}((I+C+C^2)(I+D+D^2+D^3))^*(I+C+C^2)(I+D+D^2+D^3), where τ\tau is the tracial state on the group von Neumann algebra L(T)L(T). Our extensive numerical computations suggest that 112(I+C+C2)(I+D+D2+D3)3.28,\frac1{\sqrt{12}}||(I+C+C^2)(I+D+D^2+D^3)||\approx 3.28, and thus that FF might be non-amenable. However, we can in no way rule out that 112(I+C+C2)(I+D+D2+D3)=2+2\frac1{\sqrt{12}}||(I+C+C^2)(I+D+D^2+D^3)||=\, 2+\sqrt2.

Keywords

Cite

@article{arxiv.1705.00198,
  title  = {Computational explorations of the Thompson group T for the amenability problem of F},
  author = {S. Haagerup and U. Haagerup and M. Ramirez-Solano},
  journal= {arXiv preprint arXiv:1705.00198},
  year   = {2018}
}

Comments

Accepted for publication in the journal Experimental Mathematics. Updated with the referee suggestions