English

Are Unitarizable Groups Amenable?

Operator Algebras 2007-05-23 v2 Representation Theory

Abstract

We give a new formulation of some of our recent results on the following problem: if all uniformly bounded representations on a discrete group GG are similar to unitary ones, is the group amenable? In \S 5, we give a new proof of Haagerup's theorem that, on non-commutative free groups, there are Herz-Schur multipliers that are not coefficients of uniformly bounded representations. We actually prove a refinement of this result involving a generalization of the class of Herz-Schur multipliers, namely the class Md(G)M_d(G) which is formed of all the functions f ⁣:G\bbCf\colon G\to {\bb C} such that there are bounded functions ξi ⁣:GB(Hi,Hi1)\xi_i\colon G\to B(H_i, H_{i-1}) (HiH_i Hilbert) with H0=\bbCH_0 = {\bb C}, Hd=\bbCH_d ={\bb C} such that f(t1t2...td)=ξ1(t1)ξ2(t2)...ξd(td).tiGf(t_1t_2... t_d) = \xi_1(t_1) \xi_2(t_2)... \xi_d(t_d).\qquad \forall t_i\in G We prove that if GG is a non-commutative free group, for any d1d\ge 1, we have Md(G)Md+1(G),M_d(G)\not= M_{d+1}(G), and hence there are elements of Md(G)M_d(G) which are not coefficients of uniformly bounded representations. In the case d=2d=2, Haagerup's theorem implies that M2(G)M4(G).M_2(G)\not= M_{4}(G).

Keywords

Cite

@article{arxiv.math/0405282,
  title  = {Are Unitarizable Groups Amenable?},
  author = {Gilles Pisier},
  journal= {arXiv preprint arXiv:math/0405282},
  year   = {2007}
}

Comments

Minor corrections and clarifications