English

An attempt of proof of Riemann Hypothesis

General Mathematics 2020-05-18 v2

Abstract

This paper deals with an attempt of proof of the Riemann Hypothesis (RH). Let T>1010T>10^{10} arbitrarily large. Let the region ΩT={z=x+iy  12<x<1, 0<y<T}.\Omega_T=\Big\{z=x+i y\ \Big|\ \frac{1}{2}<x<1, \ 0<y<T\Big\}. There is a finite number NTN_T of roots of ζ(z)\zeta(z) in ΩT\Omega_T. The aim of the paper is to prove that NT=0N_T=0. Suppose that NT>0N_T>0. There exists at least one root ρ=12+u+iγ\rho=\frac{1}{2}+{\bf u}+i\gamma whose real part is greater or equal to the real part of all the other roots in ΩT\Omega_T. Let v32v\geq \frac{3}{2}. Let ε>0\varepsilon>0 arbitrarily small. We prove that f(z)=ζ(z)ζ(z)f(z)=\frac{\zeta'(z)}{\zeta(z)} is analytic in the open disk Ωε={z(ρ+ε2+v)}<v.\Omega_\varepsilon=\Big\{ \Big|z-\Big(\rho+\frac{\varepsilon}{2}+v\Big)\Big|\Big\}< v. Let s=ρ+εs=\rho+\varepsilon. We prove, from the Taylor series of ζ(s)\zeta(s), that f(s)1εf(s)\sim \frac{1}{\varepsilon}\rightarrow \infty when ε0\varepsilon\rightarrow 0, and that, through the representation of f(s)f(s) as a Taylor series, f(s)=f(c0)(vε2)f(c0)+(vε2)22!f(c0)(vε2)33!f(3)(c0)+\mbox for c0=ρ+ε2+v,f(s)=f(c_0)-(v-\frac{\varepsilon}{2})f'(c_0) +\frac{(v-\frac{\varepsilon}{2})^2}{2!}f''(c_0)-\frac{(v-\frac{\varepsilon}{2})^3}{3!}f^{(3)}(c_0)+\dots\mbox{\ for\ }c_0=\rho+\frac{\varepsilon}{2}+v, in Ωε\Omega_\varepsilon, that f(s)↛f(s)\not\rightarrow \infty when ε0\varepsilon\rightarrow 0, a contradiction which allows us to prove RH.

Keywords

Cite

@article{arxiv.2004.00460,
  title  = {An attempt of proof of Riemann Hypothesis},
  author = {Roland Quême},
  journal= {arXiv preprint arXiv:2004.00460},
  year   = {2020}
}

Comments

This paper contains an irrecoverable error paragraph 6 page 4