English

Additive uniqueness of $\mathtt{PRIMES}-1$ for multiplicative functions

Number Theory 2017-08-11 v1

Abstract

Let PRIMES\mathtt{PRIMES} be the set of all primes. We show that a multiplicative function which satisfies f(p+q2)=f(p)+f(q)f(2) for p,qPRIMES f(p+q-2) = f(p) + f(q) - f(2) \text{ for }p,q \in \mathtt{PRIMES} is one of the following: \begin{enumerate} \item ff is the identity function \item ff is the constant function with f(n)=1f(n)=1 \item f(n)=0f(n)=0 for n2n \ge2 unless nn is odd and squareful. \end{enumerate} As a consequence, a multiplicative function which satisfies f(a+b)=f(a)+f(b) for a,bPRIMES1 f(a+b) = f(a) + f(b) \text{ for }a,b \in \mathtt{PRIMES}-1 is the identity function.

Keywords

Cite

@article{arxiv.1708.03037,
  title  = {Additive uniqueness of $\mathtt{PRIMES}-1$ for multiplicative functions},
  author = {Poo-Sung Park},
  journal= {arXiv preprint arXiv:1708.03037},
  year   = {2017}
}

Comments

6 pages

R2 v1 2026-06-22T21:11:01.337Z