English

About the matrix function X->AX+XA

Rings and Algebras 2012-10-03 v1

Abstract

Let K be an infinite field such that its characteristic is not 2. We show that, for every AMn(K)A\in\mathcal{M}_n(K) such that rank(A)n/2\mathrm{rank}(A)\geq n/2, there exists BMn(K)B\in\mathcal{M}_n(K) such that BB is similar to AA and A+BA+B is invertible. Let KK be a subfield of R\mathbb{R}. We show that, if nn is even, then for every XMn(K)X\in\mathcal{M}_n(K), det(AX+XA)0\det(AX+XA)\geq 0 if and only if either rank(A)<n/2\mathrm{rank}(A)<n/2 or there exists αK,α0\alpha\in K,\alpha\leq 0, such that A2=αInA^2=\alpha I_n.

Keywords

Cite

@article{arxiv.1210.0766,
  title  = {About the matrix function X->AX+XA},
  author = {Gerald Bourgeois},
  journal= {arXiv preprint arXiv:1210.0766},
  year   = {2012}
}

Comments

7 pages

R2 v1 2026-06-21T22:14:40.850Z