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A proof of the peak polynomial positivity conjecture

Combinatorics 2016-05-06 v1

Abstract

We say that a permutation π=π1π2πnSn\pi=\pi_1\pi_2\cdots \pi_n \in \mathfrak{S}_n has a peak at index ii if πi1<πi>πi+1\pi_{i-1} < \pi_i > \pi_{i+1}. Let P(π)\mathcal{P}(\pi) denote the set of indices where π\pi has a peak. Given a set SS of positive integers, we define PS(n)={πSn:P(π)=S}\mathcal{P}_S(n)=\{\pi\in\mathfrak{S}_n:\mathcal{P}(\pi)=S\}. In 2013 Billey, Burdzy, and Sagan showed that for subsets of positive integers SS and sufficiently large nn, PS(n)=pS(n)2nS1| \mathcal{P}_S(n)|=p_S(n)2^{n-|S|-1} where pS(x)p_S(x) is a polynomial depending on SS. They gave a recursive formula for pS(x)p_S(x) involving an alternating sum, and they conjectured that the coefficients of pS(x)p_S(x) expanded in a binomial coefficient basis centered at max(S)\max(S) are all nonnegative. In this paper we introduce a new recursive formula for PS(n)|\mathcal{P}_S(n)| without alternating sums, and we use this recursion to prove that their conjecture is true.

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Cite

@article{arxiv.1605.01708,
  title  = {A proof of the peak polynomial positivity conjecture},
  author = {Alexander Diaz-Lopez and Pamela E. Harris and Erik Insko and Mohamed Omar},
  journal= {arXiv preprint arXiv:1605.01708},
  year   = {2016}
}

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7 pages