English

A new upper bound to (a variant of) the pancake problem

Combinatorics 2022-11-29 v1

Abstract

The "pancake problem" asks how many prefix reversals are sufficient to sort any permutation πSk\pi \in \mathcal{S}_k to the identity. We write f(k)f(k) to denote this quantity. The best known bounds are that 1514kO(1)f(k)1811k+O(1)\frac{15}{14}k -O(1) \le f(k)\le \frac{18}{11}k+O(1). The proof of the upper bound is computer-assisted, and considers thousands of cases. We consider h(k)h(k), how many prefix and suffix reversals are sufficient to sort any πSk\pi \in \mathcal{S}_k. We observe that 1514kO(1)h(k)\frac{15}{14}k -O(1)\le h(k) still holds, and give a human proof that h(k)32k+O(1)h(k) \le \frac{3}{2}k +O(1). The constant "32\frac{3}{2}" is a natural barrier for the pancake problem and this variant, hence new techniques will be required to do better.

Keywords

Cite

@article{arxiv.2211.14678,
  title  = {A new upper bound to (a variant of) the pancake problem},
  author = {Zach Hunter},
  journal= {arXiv preprint arXiv:2211.14678},
  year   = {2022}
}

Comments

9 pages, comments welcome!