English

A formula for the number of the spanning trees of line graphs

Combinatorics 2015-07-31 v2

Abstract

Let G=(V,E)G=(V,E) be a loopless graph and T(G)\mathcal{T}(G) be the set of all spanning trees of GG. Let L(G)L(G) be the line graph of the graph GG and t(L(G))t(L(G)) be the number of spanning trees of L(G)L(G). Then, by using techniques from electrical networks, we obtain the following formula: t(L(G))=1vVd2(v)TT(G)[e=xyTd(x)d(y)][e=uvE\T[d(u)+d(v)]]. t(L(G)) = \frac{1}{\prod_{v\in V}d^2(v)}\sum_{T\subseteq \mathcal{T}(G)}\big[\prod_{e = xy\in T}d(x)d(y)\big]\big[\prod_{e = uv\in E\backslash T}[d(u)+d(v)]\big]. As a result, we provide a very simple and different proof of the formula on the number of spanning trees of some irregular line graphs, and give a positive answer to a conjecture proposed by Yan [J. Combin. Theory Ser. A 120 (2013) no. 7, 1642-1648]. By applying our formula we also derive the number of spanning trees of circulant line graphs.

Keywords

Cite

@article{arxiv.1507.06389,
  title  = {A formula for the number of the spanning trees of line graphs},
  author = {Helin Gong and Xian'an Jin},
  journal= {arXiv preprint arXiv:1507.06389},
  year   = {2015}
}

Comments

We want to withdraw this paper, since there are inappropriate expressions in the Abstract and Introduction