English

2-adic Stirling functions and their zeros

Combinatorics 2014-02-04 v1 Number Theory

Abstract

Let Pn(x)=1n!(n2i+1)(2i+1)xP_n(x)=\frac1{n!}\sum\binom n{2i+1}(2i+1)^x. This extends to a continuous function on the 2-adic integers, the nnth 2-adic partial Stirling function. We show that (1)n+1Pn(-1)^{n+1}P_n is the only 2-adically continuous approximation to S(x,n)S(x,n), the Stirling number of the second kind. We present extensive information about the zeros of PnP_n, for which there are many interesting patterns. We prove that if e2e\ge2 and 2e+1n2e+42^e+1\le n\le 2^e+4, then PnP_n has exactly 2e12^{e-1} zeros, one in each mod 2e12^{e-1} congruence. We study the relationship between the zeros of P2e+ΔP_{2^e+\Delta} and PΔP_\Delta, for 1Δ2e1\le\Delta\le 2^e, and the convergence of P2e+Δ(x)P_{2^e+\Delta}(x) as ee\to\infty.

Keywords

Cite

@article{arxiv.1402.0433,
  title  = {2-adic Stirling functions and their zeros},
  author = {Donald M. Davis},
  journal= {arXiv preprint arXiv:1402.0433},
  year   = {2014}
}

Comments

25 pages

R2 v1 2026-06-22T03:00:00.118Z