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Related papers: 2-adic Stirling functions and their zeros

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In this paper, we investigate the 2-adic valuations of the Stirling numbers $S(n, k)$ of the second kind. We show that $v_2(S(4i, 5))=v_2(S(4i+3, 5))$ if and only if $i\not\equiv 7\pmod {32}$. This confirms a conjecture of Amdeberhan, Manna…

Number Theory · Mathematics 2012-06-26 Shaofang Hong , Jianrong Zhao , Wei Zhao

Let S(n,k) denote the Stirling numbers of the second kind. We prove that the p-adic limit of S(p^e a + c, p^e b + d) as e goes to infinity exists for all integers a, b, c, and d. We call the limiting p-adic integer S(p^\infty a + c,…

Number Theory · Mathematics 2013-07-30 Donald M. Davis

Let $n$ and $k$ be positive integers. We denote by $v_2(n)$ the 2-adic valuation of $n$. The Stirling numbers of the first kind, denoted by $s(n,k)$, counts the number of permutations of $n$ elements with $k$ disjoint cycles. In recent…

Number Theory · Mathematics 2018-12-12 Min Qiu , Shaofang Hong

In this paper, we use our previous study of the higher order Bernoulli numbers $B_n^{(l)}$ to investigate the $p$-adic properties of the Stirling numbers of the second kind $S(n,k)$. For example, we give a new, greatly simplified proof of…

Number Theory · Mathematics 2018-05-04 Arnold Adelberg

Let $m, n, k$ and $c$ be positive integers. Let $\nu_2(k)$ be the 2-adic valuation of $k$. By $S(n,k)$ we denote the Stirling numbers of the second kind. In this paper, we first establish a convolution identity of the Stirling numbers of…

Number Theory · Mathematics 2014-08-01 Wei Zhao , Jianrong Zhao , Shaofang Hong

The partial Stirling numbers T_n(k) used here are defined as the sum over odd values of i of (n choose i) i^k. Their 2-exponents nu(T_n(k)) are important in algebraic topology. We provide many specific results, applying to all values of n,…

Number Theory · Mathematics 2011-09-23 Donald M. Davis

Let $n,k,a$ and $c$ be positive integers and $b$ be a nonnegative integer. Let $\nu_2(k)$ and $s_2(k)$ be the 2-adic valuation of $k$ and the sum of binary digits of $k$, respectively. Let $S(n,k)$ be the Stirling number of the second kind.…

Number Theory · Mathematics 2014-03-19 Jianrong Zhao , Shaofang Hong , Wei Zhao

We generalize results on the $p$-adic valuations of $S(n,k)$, the Stirling number of the second kind and $s(n,k)$ the Stirling number of the first kind. We have several new estimates for these valuations, along with criteria for when the…

Number Theory · Mathematics 2021-11-18 Arnold Adelberg , Tamas Lengyel

We study the 2-adic behavior of the number of domino tilings of a 2n-by-2n square as nvaries. It was previously known that this number was of the form 2^n f(n)^2, where f(n) is an odd, positive integer. We show that the function f is…

Combinatorics · Mathematics 2007-05-23 Henry Cohn

The aim of this paper is to prove conjectures concerning $p$-adic valuations of Stirling numbers of the second kind $S(n,k)$, $n,k\in\mathbb{N}_+$, stated by Amdeberhan, Manna and Moll and Berrizbeitia et al., where $p$ is a prime number.…

Number Theory · Mathematics 2018-03-14 Piotr Miska

In this paper, the polynomials $P_a(x)=x^{2^l+1}+x+a$ with $a\in\mathrm{GF}(2^k)$ are studied. New criteria for the number of zeros of $P_a(x)$ in $\mathrm{GF}(2^k)$ are proved. In particular, a criterion for $P_a(x)$ to have exactly one…

Discrete Mathematics · Computer Science 2009-10-07 Tor Helleseth , Alexander Kholosha

In this article, we give a positive answer to a question posed in 1960 by D.S. Mitrinovi\'{c} and R.S. Mitrinovi\'{c} (see: D.S. Mitrinovi\'{c} et R.S. Mitrinovi\'{c}, Tableaux qui fournissent des polyn\^{o}mes de Stirling, Publications de…

Combinatorics · Mathematics 2014-02-25 Farid Bencherif , Tarek Garici

The odd part of 2^e! as e approaches infinity leads to a 2-adic integer z. The bits of z were publicized in OEIS-A359349, where two conjectures were made, relevant to computing z. We prove both of those conjectures. A second 2-adic integer,…

Number Theory · Mathematics 2025-10-28 Donald M. Davis

For positive integers m and n, denote S(m,n) as the associated Stirling number of the second kind and let z be a complex variable. In this paper, we introduce the Stirling functions S(m,n,z) which satisfy S(m,n,z) = S(m,n) for any z which…

Number Theory · Mathematics 2017-01-03 Matthew A Williams

Several new estimates for the 2-adic valuations of Stirling numbers of the second kind are proved. These estimates, together with criteria for when they are sharp, lead to improvements in several known theorems and their proofs, as well as…

Number Theory · Mathematics 2019-12-04 Arnold Adelberg

Let n and k be natural numbers and let S(n,k) denote the Stirling numbers of the second kind. It is a conjecture of Wilf that the alternating sum \sum_{j=0}^{n} (-1)^{j} S(n,j) is nonzero for all n>2. We prove this conjecture for all n not…

Number Theory · Mathematics 2021-02-03 Stefan de Wannemacker , Thomas Laffey , Robert Osburn

The numbers e_p(k,n) defined as min(nu_p(S(k,j)j!): j >= n) appear frequently in algebraic topology. Here S(k,j) is the Stirling number of the second kind, and nu_p(-) the exponent of p. The author and Sun proved that if L is sufficiently…

Number Theory · Mathematics 2008-07-17 Donald M Davis

Let K_n denote the smaller mode of the nth row of Stirling numbers of the second kind S(n, k). Using a probablistic argument, it is shown that for all n>=2, [exp(w(n))]-2<=K_n<=[exp(w(n))]+1, where [x] denotes the integer part of x, and…

Combinatorics · Mathematics 2009-09-12 Yaming Yu

For all integers $n \geq k \geq 1$, define $H(n,k) := \sum 1 / (i_1 \cdots i_k)$, where the sum is extended over all positive integers $i_1 < \cdots < i_k \leq n$. These quantities are closely related to the Stirling numbers of the first…

Number Theory · Mathematics 2017-08-29 Paolo Leonetti , Carlo Sanna

This is an expanded version of our earlier paper. Let the $n$th partial sum of the Taylor series $e = \sum_{r=0}^{\infty} 1/r!$ be $A_n/n!$, and let $p_k/q_k$ be the $k$th convergent of the simple continued fraction for $e$. Using a recent…

Number Theory · Mathematics 2010-06-02 Jonathan Sondow , Kyle Schalm
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