English

When a meromorphic function that omits three values has a bounded type

Complex Variables 2026-04-08 v1

Abstract

Suppose that a function FF is meromorphic in the domain H(m)={z:Imz>m(Rez)}\mathbb H(-m) = \{ z : \mathrm{Im}\, z > -m(\mathrm{Re}\, z) \}, where mm is an even, positive, and continuous function that does not increase on R0\mathbb R_{\ge 0}, and suppose that FF omits there three distinct values. Then FF is of bounded type in the upper half-plane (i.e., is represented there as a quotient of two bounded analytic functions), provided that the logarithmic integral of the function mm is convergent. On the other hand, if the logarithmic integral of mm diverges, there exists a function FF meromorphic in H(m)\mathbb H(-m), that omits there three distinct values, and which is of unbounded type in the upper half-plane. This result is motivated by a century old question originating with Rolf Nevanlinna, which remains unsettled.

Keywords

Cite

@article{arxiv.2604.06136,
  title  = {When a meromorphic function that omits three values has a bounded type},
  author = {Alexandre Eremenko and Aleksei Kulikov and Mikhail Sodin},
  journal= {arXiv preprint arXiv:2604.06136},
  year   = {2026}
}

Comments

16 pages, the comments are welcome

R2 v1 2026-07-01T11:57:49.811Z