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Three-Body Inertia Tensor

Classical Physics 2021-09-01 v1

Abstract

We derive a general formula for the inertia tensor of a three-body system. By employing three independent Lagrange undetermined multipliers to express the vectors corresponding to the sides in terms of the position vectors of the vertices, we present the general covariant expression for the inertia tensor of the three particles of different masses. If ma/a=mb/b=mc/c=ρm_a/a=m_b/b=m_c/c=\rho, then the center of mass coincides with the incenter of the triangle and the moment of inertia about the normal axis passing the center of mass is I=ρabcI=\rho abc, where mam_a, mbm_b, and mcm_c are the masses of the particles at AA, BB, and CC, respectively, and aa, bb, and cc are the lengths of the line segments BC\overline{BC}, CA\overline{CA}, and AB\overline{AB}, respectively. The derivation and the corresponding results are closely related to the famous Heron's formula for the area of a triangle.

Keywords

Cite

@article{arxiv.2006.03455,
  title  = {Three-Body Inertia Tensor},
  author = {June-Haak Ee and Dong-Won Jung and U-Rae Kim and Dohyun Kim and Jungil Lee},
  journal= {arXiv preprint arXiv:2006.03455},
  year   = {2021}
}

Comments

14 pages, 3 figures

R2 v1 2026-06-23T16:05:26.161Z