English

Some Algebraic Questions about the Reed-Muller Code

Rings and Algebras 2024-03-07 v2

Abstract

Let Rq(r,n)R_q(r,n) denote the rrth order Reed-Muller code of length qnq^n over Fq\Bbb F_q. We consider two algebraic questions about the Reed-Muller code. Let Hq(r,n)=Rq(r,n)/Rq(r1,n)H_q(r,n)=R_q(r,n)/R_q(r-1,n). (1) When q=2q=2, it is known that there is a "duality" between the actions of GL(n,F2)\text{GL}(n,\Bbb F_2) on H2(r,n)H_2(r,n) and on H2(r,n)H_2(r',n), where r+r=nr+r'=n. The result is false for a general qq. However, we find that a slightly modified duality statement still holds when qq is a prime or r<charFqr<\text{char}\,\Bbb F_q. (2) Let F(Fqn,Fq)\mathcal F(\Bbb F_q^n,\Bbb F_q) denote the Fq\Bbb F_q-algebra of all functions from Fqn\Bbb F_q^n to Fq\Bbb F_q. It is known that when qq is a prime, the Reed-Muller codes {0}=Rq(1,n)Rq(0,n)Rq(n(q1),n)=F(Fqn,Fq)\{0\}=R_q(-1,n)\subset R_q(0,n)\subset\cdots\subset R_q(n(q-1),n)=\mathcal F(\Bbb F_q^n,\Bbb F_q) are the only AGL(n,Fq)\text{AGL}(n,\Bbb F_q)-submodules of F(Fqn,Fq)\mathcal F(\Bbb F_q^n,\Bbb F_q). In particular, Hq(r,n)H_q(r,n) is an irreducible GL(n,Fq)\text{GL}(n,\Bbb F_q)-module when qq is a prime. For a general qq, Hq(r,n)H_q(r,n) is not necessarily irreducible. We determine all its submodules and the factors in its composition series. The factors of the composition series of Hq(r,n)H_q(r,n) provide an explicit family of irreducible representations of GL(n,Fq)\text{GL}(n,\Bbb F_q) over Fq\Bbb F_q.

Cite

@article{arxiv.2209.00169,
  title  = {Some Algebraic Questions about the Reed-Muller Code},
  author = {Xiang-dong Hou},
  journal= {arXiv preprint arXiv:2209.00169},
  year   = {2024}
}

Comments

21 pages, 2 figures, 2 tables

R2 v1 2026-06-28T00:31:57.834Z