English

On weak-type $(1,\,1)$ for averaging type operators

Functional Analysis 2023-01-13 v1

Abstract

It is known that, due to the fact that L1,L^{1, \infty} is not a Banach space, if (Tj)j(T_j)_j is a sequence of bounded operators so that Tj:L1L1,, T_j:L^1\longrightarrow L^{1, \infty}, with norm less than or equal to Tj||T_j|| and jTj<\sum_j ||T_j||<\infty, nothing can be said about the operator T=jTjT=\sum_j T_j. This is the origin of many difficult and open problems. However, if we assume that Tj:L1(u)L1,(u),uA1, T_j:L^1(u)\longrightarrow L^{1, \infty}(u), \qquad \forall u\in A_1, with norm less than or equal to φ(uA1)Tj\varphi(||u||_{A_1})||T_j||, where φ\varphi is a nondecreasing function and A1A_1 the Muckenhoupt class of weights, then we prove that, essentially, T:L1(u)L1,(u),uA1. T:L^1(u) \longrightarrow L^{1, \infty}(u), \qquad \forall u\in A_1. We shall see that this is the case of many interesting problems in Harmonic Analysis.

Keywords

Cite

@article{arxiv.2301.05201,
  title  = {On weak-type $(1,\,1)$ for averaging type operators},
  author = {S. Baena-Miret and M. J. Carro},
  journal= {arXiv preprint arXiv:2301.05201},
  year   = {2023}
}
R2 v1 2026-06-28T08:10:33.411Z