English

On some mean value results for the zeta-function and a divisor problem II

Number Theory 2015-12-07 v2

Abstract

Let d(n)d(n) be the number of divisors of nn, let γ\gamma denote Euler's constant and Δ(x):=nxd(n)x(logx+2γ1) \Delta(x) := \sum_{n\le x}d(n) - x(\log x + 2\gamma -1) denote the error term in the classical Dirichlet divisor problem, and let ζ(s)\zeta(s) denote the Riemann zeta-function. It is shown that 0TΔ(t)ζ(1/2+it)2dtT(logT)4. \int_0^T\Delta(t)|\zeta(1/2+it)|^2\,dt \ll T(\log T)^{4}. Further, if 2k82\le k\le 8 is a fixed integer, then we prove the asymptotic formula 1TΔk(t)ζ(1/2+it)2dt=c1(k)T1+k4logT+c2(k)T1+k4+Oε(T1+k4ηk+ε), \int_1^{T}\Delta^{k}(t)|\zeta(1/2+it)|^2\,dt=c_1(k)T^{1+\frac k4}\log T+ c_2(k)T^{1+\frac k4}+O_\varepsilon(T^{1+\frac k4-\eta_k+\varepsilon}), where c1(k)c_1(k) and c2(k)c_2(k) are explicit constants, and where η2=3/20,η3=η4=1/10, η5=3/80, η6=35/4742, η7=17/6312, η8=8/9433.\eta_2= 3/20, \eta_3= \eta_4=1/10,\ \eta_5=3/80,\ \eta_6=35/4742,\ \eta_7=17/6312,\ \eta_8=8/9433. The results depend on the power moments of Δ(t)\Delta(t) and E(T)E(T), the classical error term in the asymptotic formula for the mean square of ζ(1/2+it)|\zeta(1/2+it)|.

Keywords

Cite

@article{arxiv.1502.00406,
  title  = {On some mean value results for the zeta-function and a divisor problem II},
  author = {Aleksandar Ivić and Wenguang Zhai},
  journal= {arXiv preprint arXiv:1502.00406},
  year   = {2015}
}

Comments

31 pages

R2 v1 2026-06-22T08:18:44.290Z