English

On CH + 2^{aleph_1}-> (alpha)^2_2 for alpha < omega_2

Logic 2009-09-25 v1

Abstract

We prove the consistency of ``CH + 2^{aleph_1} is arbitrarily large + 2^{aleph_1} not-> (omega_1 x omega)^2_2''. If fact, we can get 2^{aleph_1} not-> [omega_1 x omega]^2_{aleph_0}. In addition to this theorem, we give generalizations to other cardinals.

Cite

@article{arxiv.math/9308212,
  title  = {On CH + 2^{aleph_1}-> (alpha)^2_2 for alpha < omega_2},
  author = {Saharon Shelah},
  journal= {arXiv preprint arXiv:math/9308212},
  year   = {2009}
}
R2 v1 2026-07-22T17:54:25.893Z