English

Numerical radius inequalities of bounded linear operators and $(\alpha,\beta)$-normal operators

Functional Analysis 2023-01-11 v1

Abstract

We obtain various upper bounds for the numerical radius w(T)w(T) of a bounded linear operator TT defined on a complex Hilbert space H\mathcal{H}, by developing the upper bounds for the α\alpha-norm of TT, which is defined as Tα=sup{αTx,x2+(1α)Tx2:xH,x=1}\|T\|_{\alpha}= \sup \left\{ \sqrt{\alpha |\langle Tx,x \rangle|^2+ (1-\alpha)\|Tx\|^2 } : x\in \mathcal{H}, \|x\|=1 \right\} for 0α1 0\leq \alpha \leq 1 . Further, we prove that \begin{eqnarray*} w(T) &\leq & \sqrt{\left( \min_{\alpha \in [0,1]}\left\| \alpha |T|+(1-\alpha)|T^*| \right\| \right) \|T\|} \,\,\,\, \leq \,\, \,\, \|T\|. \end{eqnarray*} For 0α1β,0\leq \alpha \leq 1 \leq \beta, the operator TT is called (α,β)(\alpha,\beta)-normal if α2TTTTβ2TT\alpha^2 T^*T\leq TT^*\leq \beta^2 T^*T holds. Note that every invertible operator is an (α,β)(\alpha,\beta)-normal operator for suitable values of α\alpha and β\beta. Among other lower bound for the numerical radius of an (α,β)(\alpha,\beta)-normal operator TT, we show that \begin{eqnarray*} w(T) &\geq & \sqrt{\max \left\{ 1+\alpha^2, 1+\frac{1}{\beta^2}\right\} \frac{\|T\|^2}{4}+ \frac {\left| \|\Re(T)\|^2-\|\Im(T)\|^2 \right|}2} &\geq & \max \left\{ \sqrt{1+\alpha^2}, \sqrt{1+\frac{1}{\beta^2}} \right\} \frac{\|T\|}{2} & > & \frac{\|T\|}2, \end{eqnarray*} where (T)\Re(T) and (T)\Im(T) are the real part and imaginary part of TT, respectively.

Keywords

Cite

@article{arxiv.2301.03877,
  title  = {Numerical radius inequalities of bounded linear operators and $(\alpha,\beta)$-normal operators},
  author = {Pintu Bhunia},
  journal= {arXiv preprint arXiv:2301.03877},
  year   = {2023}
}

Comments

10 pages

R2 v1 2026-06-28T08:08:23.470Z