English

Hindman's theorem and idempotent types

Logic 2015-08-17 v1 Combinatorics

Abstract

Motivated by a question of Di Nasso, we prove that Hindman's theorem is equivalent to the existence of idempotent types in countable complete extensions of Peano Arithmetic.

Cite

@article{arxiv.1508.03613,
  title  = {Hindman's theorem and idempotent types},
  author = {Uri Andrews and Isaac Goldbring},
  journal= {arXiv preprint arXiv:1508.03613},
  year   = {2015}
}

Comments

6 pages

R2 v1 2026-06-22T10:34:06.053Z