Hilbert's Tenth Problem for some Noncommutative Rings
Abstract
We consider Hilbert's tenth problem for two families of noncommutative rings. Let be a field of characteristic . We start by showing that Hilbert's tenth problem has a negative answer over the twisted polynomial ring and its left division ring of fractions . We prove that the recursively enumerable sets and Diophantine sets of coincide. We reduce Hilbert's tenth problem over and , the twisted version of the power series and Laurent series, to the commutative case. Finally, we show that the different models of in we created are all equivalent in some sense which we will define. We then move on to the second family of rings, coming from differential polynomials. We show that Hilbert's tenth problem over has a negative answer. We prove that Hilbert's tenth problem over the left division ring of fractions can be reduced to Hilbert's tenth problem over where is the field of constants of . This gives a negative answer for if the field of constants is and for if it is .
Cite
@article{arxiv.2410.03485,
title = {Hilbert's Tenth Problem for some Noncommutative Rings},
author = {A. Eggink},
journal= {arXiv preprint arXiv:2410.03485},
year = {2024}
}
Comments
20 pages, 0 figures