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Related papers: Maximal subgroups of direct products

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We give here the exact maximal subgroup growth of two classes of polycyclic groups. Let $G_k = \langle x_1, x_2, ..., x_k \mid x_ix_jx_i^{-1}x_j \text{ for all } i < j \rangle$. So $G_k = \mathbb{Z} \rtimes (\mathbb{Z} \rtimes (\mathbb{Z}…

Group Theory · Mathematics 2019-11-19 Andrew James Kelley , Elizabeth Ciorsdan Dwyer Wolfe

Let $m_n(G)$ denote the number of maximal subgroups of $G$ of index $n$. An upper bound is given for the degree of maximal subgroup growth of all polycyclic metabelian groups $G$ (i.e., for $\limsup \frac{\log m_n(G)}{\log n}$, the degree…

Group Theory · Mathematics 2018-07-11 Andrew James Kelley

We prove the following results: (1) Every group is a maximal subgroup of some free idempotent generated semigroup. (2) Every finitely presented group is a maximal subgroup of some free idempotent generated semigroup arising from a finite…

Group Theory · Mathematics 2011-08-02 Robert Gray , Nik Ruskuc

The maximal normal subgroup growth type of a finitely generated group is $n^{\log n}$. Very little is known about groups with this type of growth. In particular, the following is a long standing problem: Let $\Gamma$ be a group and $\Delta$…

Group Theory · Mathematics 2019-06-18 Yiftach Barnea , Jan-Christoph Schlage-Puchta

This paper studies the locally uniform exponential growth and product set growth for a finitely generated group $G$ acting properly on a finite product of hyperbolic spaces. Under the assumption of coarsely dense orbits or shadowing…

Group Theory · Mathematics 2024-07-23 Renxing Wan , Wenyuan Yang

Gray and Ruskuc have shown that any group G occurs as the maximal subgroup of some free idempotent generated semigroup IG(E) on a biordered set of idempotents E, thus resolving a long standing open question. Given the group G, they make a…

Rings and Algebras · Mathematics 2012-09-07 Victoria Gould , Dandan Yang

We determine all the ways in which a direct product of two finite groups can be expressed as the set-theoretical union of proper subgroups in a family of minimal cardinality.

Group Theory · Mathematics 2012-11-26 Andrea Lucchini , Martino Garonzi

For a finite group $G$ we investigate the difference between the maximum size MaxDim$(G)$ of an "independent" family of maximal subgroups of $G$ and maximum size $m(G)$ of an irredundant sequence of generators of $G$. We prove that…

Group Theory · Mathematics 2015-02-25 Eloisa Detomi , Andrea Lucchini

We provide lower estimates on the minimal number of generators of the profinite completion of free products of finite groups. In particular, we show that if C_1,...,C_n are finite cyclic groups then there exists a finite group G which is…

Group Theory · Mathematics 2007-05-23 Miklos Abert , Pal Hegedus

The deep theory of approximate subgroups establishes 3-step product growth for subsets of finite simple groups $G$ of Lie type of bounded rank. In this paper we obtain 2-step growth results for representations of such groups $G$ (including…

Representation Theory · Mathematics 2021-04-26 Michael Larsen , Aner Shalev , Pham Huu Tiep

For each group G which decomposes into a finitary direct product of free groups of finite rank we construct a regular band B such that the free idempotent generated semigroup over B contains a maximal subgroup isomorphic to G. In…

Group Theory · Mathematics 2013-03-26 Igor Dolinka

Let $w = w(x_1,..., x_n)$ be a word, i.e. an element of the free group $F =<x_1,...,x_n>$ on $n$ generators $x_1,..., x_n$. The verbal subgroup $w(G)$ of a group $G$ is the subgroup generated by the set $\{w (g_1,...,g_n)^{\pm 1} | g_i \in…

Group Theory · Mathematics 2010-04-01 Jon Gonzalez-Sanchez , Benjamin Klopsch

If $G_1,...,G_n$ are limit groups and $S\subset G_1\times...\times G_n$ is of type $\FP_n(\mathbb Q)$ then $S$ contains a subgroup of finite index that is itself a direct product of at most $n$ limit groups. This settles a question of Sela.

Group Theory · Mathematics 2007-11-07 Martin R Bridson , James Howie , Charles F Miller , Hamish Short

Given an arbitrary group $G$ we construct a semigroup of idempotents (band) $B_G$ with the property that the free idempotent generated semigroup over $B_G$ has a maximal subgroup isomorphic to $G$. If $G$ is finitely presented then $B_G$ is…

Group Theory · Mathematics 2014-03-10 Igor Dolinka , Nik Ruškuc

We show that every definable group G in an o-minimal structure is definably finitely generated. That is, G contains a finite subset that is not included in any proper definable subgroup. This provides another proof, and a generalization to…

Logic · Mathematics 2023-07-25 Annalisa Conversano

For every Lie group $G$, we compute the maximal $n$ such that an $n$-fold product of nonabelian free groups embeds into $G$.

Group Theory · Mathematics 2021-02-23 Caterina Campagnolo , Holger Kammeyer

Let $G$ be a finite almost simple group. It is well known that $G$ can be generated by 3 elements, and in previous work we showed that 6 generators suffice for all maximal subgroups of $G$. In this paper we consider subgroups at the next…

Group Theory · Mathematics 2016-11-21 Timothy C. Burness , Martin W. Liebeck , Aner Shalev

Direct powers of perfect groups admit more concise presentations than one might naively suppose. If $H_1G=H_2G=0$, then $G^n$ has a presentation with $O(\log n)$ generators and $O(\log n)^3$ relators. If, in addition, there is an element…

Group Theory · Mathematics 2017-10-17 Martin R Bridson

We show that for some absolute (explicit) constant $C$, the following holds for every finitely generated group $G$, and all $d >0$: If there is some $ R_0 > \exp(\exp(Cd^C))$ for which the number of elements in a ball of radius $R_0$ in a…

Group Theory · Mathematics 2010-04-09 Yehuda Shalom , Terence Tao

Given a size-$k$ subset $S$ of a group $G$, how large can the product set $S^n$ be? We study this question, at several layers of refinement, for the infinite dihedral group. First, we give an explicit formula for the maximum size of $S^n$…

Group Theory · Mathematics 2026-03-25 Be'eri Greenfeld , George King , Xiaoxuan Li , Sam Tacheny
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