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Every simple quadrangulation of the sphere is generated by a graph called a pseudo-double wheel with two local expansions (Brinkmann et al. "Generation of simple quadrangulations of the sphere." Discrete Math., Vol. 305, No. 1-3, pp. 33-54,…

Metric Geometry · Mathematics 2012-10-08 Yohji Akama

A tiling of a topological disc by topological discs is called monohedral if all tiles are congruent. Maltby (J. Combin. Theory Ser. A 66: 40-52, 1994) characterized the monohedral tilings of a square by three topological discs. Kurusa,…

Metric Geometry · Mathematics 2023-06-27 Bushra Basit , Zsolt Lángi

Since the thesis of K. Reinhardt in 1918, it is well known that there are exactly three types of convex hexagons that can tile the plane. However, the proof of the fact is far from being complete. We prove this fact, under an assumption…

Combinatorics · Mathematics 2026-04-29 Ze Zhu , Erxiao Wang , Min Yan

Keller packings and tilings of boxes are investigated. Certain general inequality measuring a complexity of such systems is proved. A straightforward application to the unit cube tilings is given.

Combinatorics · Mathematics 2018-04-23 Krzysztof Przesławski

Let $T$ be a tile in $\mathbb{Z}^n$, meaning a finite subset of $\mathbb{Z}^n$. It may or may not tile $\mathbb{Z}^n$, in the sense of $\mathbb{Z}^n$ having a partition into copies of $T$. However, we prove that $T$ does tile $\mathbb{Z}^d$…

Combinatorics · Mathematics 2016-08-23 Vytautas Gruslys , Imre Leader , Ta Sheng Tan

We study the minimal complexity of tilings of a plane with a given tile set. We note that every tile set admits either no tiling or some tiling with O(n) Kolmogorov complexity of its n-by-n squares. We construct tile sets for which this…

Computational Complexity · Computer Science 2018-12-03 Bruno Durand , Leonid A. Levin , Alexander Shen

This paper focuses on the undecidability of translational tiling of $n$-dimensional space $\mathbb{Z}^n$ with a set of $k$ tiles. It is known that tiling $\mathbb{Z}^2$ with translated copies with a set of $8$ tiles is undecidable.…

Combinatorics · Mathematics 2025-06-24 Chao Yang , Zhujun Zhang

Several articles deal with tilings with squares and dominoes on 2-dimensional boards, but only a few on boards in 3-dimensional space. We examine a tiling problem with colored cubes and bricks of $(2\times2\times n)$-board in three…

Combinatorics · Mathematics 2021-04-01 László Németh

Let $Q_n$ be the $n$-dimensional hypercube, and let ${\rm cr}(Q_n)$ be the \textit{crossing number} of $Q_n$. Erd\H{o}s and Guy in 1973 conjectured the following equality: ${\rm cr}(Q_n)=\frac{5}{32}4^n-\lfloor\frac{n^2+1}{2}\rfloor…

Combinatorics · Mathematics 2021-12-23 Yuansheng Yang , Guoqing Wang , Haoli Wang , Yan Zhou

In this paper, we prove that it is undecidable whether a set of two polycubes can tile $\mathbb{Z}^3$ by translation. The proof involves a new technique that allows us to simulate two disconnected polycubes with two connected polycubes. By…

Combinatorics · Mathematics 2025-08-19 Yoonhu Kim

In [BNRR], it was shown that tiling of general regions with two rectangles is NP-complete, except for a few trivial special cases. In a different direction, R\'emila showed that for simply connected regions by two rectangles, the…

Combinatorics · Mathematics 2013-05-14 Igor Pak , Jed Yang

The paper provides an elementary proof of Kenyon's necessary condition for the existence of a periodic tiling of the plane by squares with given periods. A similar new result on covering both sides of a rectangle by nonoverlaping squares is…

Combinatorics · Mathematics 2020-03-12 Mikhail Dmitriev

Tilings of a surface of negative Euler characteristic by n-gons with n\ge 7 is a finite problem. We develop the algorithm for finding all the tilings for fixed number of tiles and present the calculation for tilings of surfaces of small…

Combinatorics · Mathematics 2026-04-29 Chunlin Li , Erxiao Wang , Wu Jie , Min Yan

Norine's antipodal-colouring conjecture, in a form given by Feder and Subi, asserts that whenever the edges of the discrete cube are 2-coloured there must exist a path between two opposite vertices along which there is at most one colour…

Combinatorics · Mathematics 2020-06-01 Vojtěch Dvořák

Let $\Omega\subset \mathbb{R}^d$ be a set of finite measure. The periodic tiling conjecture suggests that if $\Omega$ tiles $\mathbb{R}^d$ by translations then it admits at least one periodic tiling. Fuglede's conjecture suggests that…

Classical Analysis and ODEs · Mathematics 2024-11-14 Rachel Greenfeld , Mihail N. Kolountzakis

We establish that almost every positive integer $n$ is the sum of four cubes, two of which are at most $n^{\theta}$, as long as $\theta\geq192/869$. An asymptotic formula for the number of such representations is established when…

Number Theory · Mathematics 2010-06-29 Siu-lun Alan Lee

We study the dissection of a square into congruent convex polygons. Yuan \emph{et al.} [Dissecting the square into five congruent parts, Discrete Math. \textbf{339} (2016) 288-298] asked whether, if the number of tiles is a prime number…

Combinatorics · Mathematics 2023-06-22 Hui Rao , Lei Ren , Yang Wang

Translational tiling problems are among the most fundamental and representative undecidable problems in all fields of mathematics. Greenfeld and Tao obtained two remarkable results on the undecidability of translational tiling in recent…

Combinatorics · Mathematics 2025-08-04 Chao Yang , Zhujun Zhang

A dyadic tile of order n is any rectangle obtained from the unit square by n successive bisections by horizontal or vertical cuts. Let each dyadic tile of order n be available with probability p, independently of the others. We prove that…

Probability · Mathematics 2012-07-24 Omer Angel , Alexander E. Holroyd , Gady Kozma , Johan Wästlund , Peter Winkler

This is the eighth and final paper in a series giving a proof of the Kepler conjecture, which asserts that the density of a packing of congruent spheres in three dimensions is never greater than $\pi/\sqrt{18}\approx 0.74048...$. This is…

Metric Geometry · Mathematics 2007-05-23 Thomas C. Hales