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Related papers: A Method to Solve the Diophantine Equation $ax^2-b…

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First, we consider the equation $ax^2 - by^2 + c = 0$, with $a,b \in N*$ and $c \in Z*$, which is a generalization of Pell's equation. Here, we show that: if this equation has an integer solution and $ab$ is not a perfect square, then it…

General Mathematics · Mathematics 2007-05-23 Florentin Smarandache

We prove that for given integers b and c, the diophantine equation x^2+bx+c=y^2, has finitely many integer solutions(i.e. pairs in ZxZ),in fact an even number of such solutions(including the zero or no solutions case).We also offer an…

General Mathematics · Mathematics 2008-03-28 Konstantine "Hermes" Zelator

In this note, we find all the solutions of the Diophantine equation x^2 +2^a.3^b.11^c=y^n in nonnegative integers a, b, c, x, y, n>= 3 with x and y coprime.

Number Theory · Mathematics 2012-01-04 Ismail Naci Cangul , Musa Demirci , Ilker Inam , Florian Luca , Gokhan Soydan

This paper investigates the exponential Diophantine equation of the form $a^x+b=c^y$, where $a, b, c$ are given positive integers with $a,c \ge 2$, and $x,y$ are positive integer unknowns. We define this form as a "Type-I transcendental…

Number Theory · Mathematics 2025-10-15 Zeyu Cai

It is important in drawing techniques to find combinations of two straight lines and their angle bisectors whose slopes are all rational numbers. This problem is reduced to solving the Diophantine equation $(a-c)^2(b^2+1) = (b-c)^2(a^2+1).$…

Number Theory · Mathematics 2025-01-03 Takashi Hirotsu

We prove that the Diophantine equation (a^2 c x^k - 1)(b^2 c y^k - 1) = (abc z^k - 1)^2 has no solutions in positive integers with x, y, z > 1, k \geq 7 and a^2x^k \neq b^2y^k.

Number Theory · Mathematics 2014-11-10 E. G. Goedhart , H. G. Grundman

Let $a,b,c $ be any positive integers such that $c\mid ab$ and $d_i^\pm$ is a square free positive integer of the form $d_i^\pm=a^{2k} b^{2l}\pm i c^m$ where $k,l \geq m$ and $i=1,2.$ The main focus of this paper to find the fundamental…

Number Theory · Mathematics 2014-02-24 Zahid Raza , Hafsa Masood Malik

We give the complete solution in integers $(n,a,b,x,y)$ of the title equation when $\gcd(x,y)=1$, except for the case when $xab$ is odd.

Number Theory · Mathematics 2010-01-15 I. N. Cangül , M. Demirci , G. Soydan , N. Tzanakis

In this paper, we give all the solutions of the Diophantine equation x^2+7^{alpha}.11^{beta}=y^n, in nonnegative integers x, y, n>=3 with x and y coprime, except for the case when alpha.x is odd and beta is even.

Number Theory · Mathematics 2012-01-05 Gokhan Soydan

In this short note we present a method of solving this Diophantine equation, method which is different from Ljunggren's, Mordell's, and R.K.Guy's.

General Mathematics · Mathematics 2007-05-23 Florentin Smarandache

The main aim of this article is to find all solutions of the Diophantine equation $x^2 + p^k=y^n$ where $p \equiv 1 \pmod 4$, $\frac{p-1}{3}$ is a perfect square and the class number of $\mathbb{Z}[\sqrt{-p}]$ is $2$. In this article, I…

Number Theory · Mathematics 2024-03-25 Arkabrata Ghosh

The object of this paper is to give a new proof of all the solutions of the Diophantine equation x^2+11^m=y^n; in positive integers x, y with odd m>1 and n>=3.

Number Theory · Mathematics 2011-12-30 Gokhan Soydan , Musa Demirci , Ismail Naci Cangul

On propose une m\'ethode de r\'esolution effective de l'\'equation diophantienne $(E_2): ax^2-by^2=1$ o\`u $a$ et $b$ sont des entiers naturels non nuls et premiers entre eux. Cette m\'ethode s'appuie sur le d\'eveloppement en fraction…

Number Theory · Mathematics 2017-07-25 Lionel Ponton

The objective of the paper is to determine the complete solutions for the Diophantine equation $x^2 + 3^{\alpha}113^{\beta} = y^{\mathfrak{n}}$ in positive integers $x$ and $y$ (where $x, y \geq 1$), non-negative exponents $\alpha$ and…

Number Theory · Mathematics 2024-05-20 S. Muthuvel , R. Venkatraman

In this short note we study the existence and number of solutions in the set of integers ($Z$) and in the set of natural numbers ($N$) of Diopahntine Equations of second degree with two variables of the general form $ax^2-by^2=c$.

General Mathematics · Mathematics 2007-05-23 Florentin Smarandache

We find all solutions of Diophantine equation x^{2}+11^{2k} = y^{n} where x>=1, y>=1, n>=3 and k is natural number. We give p-adic interpretation of this equation.

Number Theory · Mathematics 2011-12-30 Ismail Naci Cangul , Gokhan Soydan , Yilmaz Simsek

In this work, we prove the following result(Theorem 1): Suppose that n is a positive integer, p an odd prime, and such that either n is congruent to 0 modulo4 and p congruent to 3 modulo8; or alternatively, n is congruent to 2 modulo4 and p…

Number Theory · Mathematics 2009-05-21 Konstantine Zelator

In this paper, we consider the equation $(a^n-2^{m})(b^n-2^{m})=x^2$. By assuming the abc conjecture is true, in [8], Luca and Walsh gave a theorem, which implies that the above equation has only finitely many solutions $n,x$ if a and b are…

Number Theory · Mathematics 2018-01-16 Zafer Şiar , Refik Keskin

Let $f(x)=x^{2}(x^{2}-1)(x^{2}-2)(x^{2}-3).$ We prove that the Diophantine equation $ f(x)=2f(y)$ has no solutions in positive integers $x$ and $y$, except $(x, y)=(1, 1)$.

Number Theory · Mathematics 2018-11-06 Sanjay Bhatter , Richa Sharma

We investigate the solvability of the Diophantine equation in the title, where $d>1$ is a square-free integer, $p, q$ are distinct odd primes and $x,y,a,b$ are unknown positive integers with $\gcd(x,y)=1$. We describe all the integer…

Number Theory · Mathematics 2021-11-11 Kalyan Chakraborty , Azizul Hoque
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