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Related papers: Necklaces, subset sums, and cyclic permutations

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Consider these two distinct combinatorial objects: (1) the necklaces of length $n$ with at most $q$ colors, and (2) the multisets of integers modulo $n$ with subset sum divisible by $n$ and with the multiplicity of each element being…

Combinatorics · Mathematics 2024-12-02 Swee Hong Chan

An $(a,b)$-difference necklace of length $n$ is a circular arrangement of the integers $0, 1, 2, \ldots , n-1$ such that any two neighbours have absolute difference $a$ or $b$. We prove that, subject to certain conditions on $a$ and $b$,…

Combinatorics · Mathematics 2020-06-30 Ethan P. White , Richard K. Guy , Renate Scheidler

We address two variants of the classical necklace counting problem from enumerative combinatorics. In both cases, we fix a finite group $\mathcal{G}$ and a positive integer $n$. In the first variant, we count the ``identity-product…

Combinatorics · Mathematics 2025-12-25 Darij Grinberg , Peter Mao

Simple formulas for the number of different cyclic and dihedral necklaces containing $n_j$ beads of the $j$-th color, $j\leq m$ and $\sum_{j=1}^mn_j=N$, are derived.

Combinatorics · Mathematics 2007-05-23 Leonid G. Fel , Yoram Zimmels

We introduce a variant of de Bruijn words that we call perfect necklaces. Fix a finite alphabet. Recall that a word is a finite sequence of symbols in the alphabet and a circular word, or necklace, is the equivalence class of a word under…

Combinatorics · Mathematics 2016-02-01 Nicolás Álvarez , Verónica Becher , Pablo A. Ferrari , Sergio A. Yuhjtman

This paper addresses the problem of finding $Q_{m,t}\left(n\right)$, the number of possible ways to partition any member $n$ of the cyclic group $\mathbb{Z}/m\mathbb{Z}$ into $t$ distinct parts. When $m$ is odd, it was previously known that…

Combinatorics · Mathematics 2019-06-04 Steven S Poon

In this paper we investigate enumeration of some classes of $n$-character strings and binary necklaces. Recall that binary necklaces are necklaces in two colors with length $n$. We prove three results (Theorems 1, 1' and 2) concerning the…

Combinatorics · Mathematics 2018-04-04 Romeo Meštrović

A necklace is an equivalence class of words of length $n$ over an alphabet under the cyclic shift (rotation) operation. As a classical object, there have been many algorithmic results for key operations on necklaces, including counting,…

Combinatorics · Mathematics 2021-11-08 Duncan Adamson , Argyrios Deligkas , Vladimir V. Gusev , Igor Potapov

We present a proof of Swee Hong Chan's conjecture establishing a bijection between the set of necklaces of length $n$ with at most $q$ colors, and the set of periodic functions $f: \mathbb{Z}_{n}\to {0, 1, ..., q-1}$ whose weighted sum is…

Combinatorics · Mathematics 2025-09-03 Jiyou Li , Yanghongbo Zhou

It is known that, when $n$ is even, the number of permutations of $\{1,2,\dots,n\}$ all of whose cycles have odd length equals the number of those all of whose cycles have even length. Adin, Heged\H{u}s and Roichman recently found a…

Combinatorics · Mathematics 2025-04-08 Sergi Elizalde

Let $G_n$ denote the $n^{\rm th}$ Gleason polynomial, whose roots correspond to parameters $c$ such that the critical point $0$ is periodic of exact period $n$ under iteration of $z^2 + c$, and let $\bar{G}_n$ denote the reduction of $G_n$…

Combinatorics · Mathematics 2025-09-25 Matthew Baker , Andrea Chen , Sophie Li , Matthew Qian

We show there is a bijection between the binary necklaces with $n$ black beads and $k$ white beads and certain $(n,k)$-codes when $n$ is prime. The main idea is to come up with a new map on necklaces called slime migration.

Combinatorics · Mathematics 2019-12-03 Suho Oh , Jina Park

For integers $n,k,s$, we give a formula for the number $T(n,k,s)$ of order $k$ subsets of the ring $\mathbb{Z}/n\mathbb{Z}$ whose sum of elements is $s$ modulo $n$. To do so, we describe explicitly a sequence of matrices $M(k)$, for…

Number Theory · Mathematics 2025-03-21 David Broadhurst , Xavier Roulleau

A necklace or bracelet is \textit{colorful} if no pair of adjacent beads are the same color. In addition, two necklaces are \textit{equivalent} if one results from the other by permuting its colors, and two bracelets are \textit{equivalent}…

Combinatorics · Mathematics 2019-03-06 Dennis S. Bernstein , Omran Kouba

We use the fact that certain cosets of the stabilizer of points are pairwise conjugate in a symmetric group $S_n$ in order to construct recurrence relations for enumerating certain subsets of $S_n$. Occasionally one can find `closed form'…

Combinatorics · Mathematics 2016-08-18 S. P. Glasby

Fix a finite alphabet. A necklace is a circular word. For positive integers $n$ and~$k$, a necklace is $(n,k)$-perfect if all words of length $n$ occur $k$ times but at positions with different congruence modulo $k$, for any convention of…

Combinatorics · Mathematics 2025-02-12 Verónica Becher , Tomás Tropea

We give subquadratic algorithms that, given two necklaces each with n beads at arbitrary positions, compute the optimal rotation of the necklaces to best align the beads. Here alignment is measured according to the p norm of the vector of…

Data Structures and Algorithms · Computer Science 2012-12-20 David Bremner , Timothy M. Chan , Erik D. Demaine , Jeff Erickson , Ferran Hurtado , John Iacono , Stefan Langerman , Mihai Patrascu , Perouz Taslakian

A grid class consists of permutations whose pictorial depiction can be partitioned into increasing and decreasing parts as determined by a given matrix. In this paper, we introduce a method for enumerating cyclic permutations in vector grid…

Combinatorics · Mathematics 2018-08-27 Kassie Archer , L. -K. Lauderdale

Let G be an additive abelian group whose finite subgroups are all cyclic. Let A_1,...,A_n (n>1) be finite subsets of G with cardinality k>0, and let b_1,...,b_n be pairwise distinct elements of G with odd order. We show that for every…

Combinatorics · Mathematics 2016-09-07 Zhi-Wei Sun

It is shown in [7] by Venkaiah in 2015 that a category of the number of generalized can be computed using the expression \begin{equation*} e(n, q) = \frac{1}{(q-1) ord(\lambda) n} \sum^{ord(\lambda)n}_{\substack{t \in \mathbb{F}_q \setminus…

Combinatorics · Mathematics 2018-08-10 V Ch Venkaiah
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