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Related papers: Approximate cycle double cover

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In this paper, a proof of the cycle double cover conjecture is presented. The cycle double cover conjecture purports that if a graph is bridgeless, then there exists a list of cycles in the graph such that every edge in the graph appears in…

Combinatorics · Mathematics 2014-04-08 P. Clarke

Given a bridgeless graph $G$, the Cycle Double Cover Conjecture posits that there is a list of cycles of $G$, such that every edge appears in exactly two cycles on the list. This conjecture was originally posed independently in 1973 by…

Combinatorics · Mathematics 2015-10-12 Mary Radcliffe

Given a bridgeless graph G, the well-known cycle double cover conjecture posits that there is a list of cycles of G, such that every edge appears in exactly two cycles. In this paper, we prove the cycle double cover conjecture. More…

Combinatorics · Mathematics 2018-11-22 A. Alipour , A. Tayebi

We study a counting version of Cycle Double Cover Conjecture. We discuss why it is more interesting to count circuits (i.e., graphs isomorphic to $C_k$ for some $k$) instead of cycles (graphs with all degrees even). We give an…

Combinatorics · Mathematics 2024-09-12 Radek Hušek , Robert Šámal

The strong cycle double cover conjecture states that for every circuit $C$ of a bridgeless cubic graph $G$, there is a cycle double cover of $G$ which contains $C$. We conjecture that there is even a 5-cycle double cover $S$ of $G$ which…

Combinatorics · Mathematics 2012-11-12 Arthur Hoffmann-Ostenhof

The cycle double cover conjecture states that a graph is bridge-free if and only if there is a family of edge-simple cycles such that each edge is contained in exactly two of them. It was formulated independently by Szekeres (1973) and…

Discrete Mathematics · Computer Science 2012-02-08 Alexander Souza

We approach the cycle double cover conjecture by looking for a circular 2-cell embedding of cubic graphs on an arbitrary surface. It is easy to see that if such an embedding exists, we can get to it from an arbitrary starting 2-cell…

Combinatorics · Mathematics 2026-05-05 Babak Ghanbari , Robert Šámal

In this paper, for each graph G, a free edge set F is defined. To study the existence of cycle double cover, the naive cycle double cover of G and F have been defined and studied. In the main theorem, the paper, based on the Kuratowski…

Combinatorics · Mathematics 2022-03-02 Ali Ghassab

A cycle double cover (CDC) of an undirected graph is a collection of the graph's cycles such that every edge of the graph belongs to exactly two cycles. We describe a constructive method for generating all the cubic graphs that have a 6-CDC…

Discrete Mathematics · Computer Science 2009-04-17 Rodrigo S. C. Leao , Valmir C. Barbosa

A conjecture of Berge suggests that every bridgeless cubic graph can have its edges covered with at most five perfect matchings. Since three perfect matchings suffice only when the graph in question is $3$-edge-colourable, the rest of cubic…

Combinatorics · Mathematics 2020-08-05 Edita Máčajová , Martin Škoviera

A "folklore conjecture, probably due to Tutte" (as described in [P.D. Seymour, Sums of circuits, Graph theory and related topics (Proc. Conf., Univ. Waterloo, 1977), pp. 341-355, Academic Press, 1979]) asserts that every bridgeless cubic…

Combinatorics · Mathematics 2011-01-14 Bojan Mohar

A theorem due to Seyffarth states that every planar $4$-connected $n$-vertex graph has a cycle double cover (CDC) containing at most $n-1$ cycles (a "small" CDC). We extend this theorem by proving that, in fact, such a graph must contain…

Combinatorics · Mathematics 2025-06-13 Jorik Jooken , Ben Seamone , Carol T. Zamfirescu

We explore the well-known Jaeger's directed cycle double cover conjecture which is equivalent to the assertion that every cubic bridgeless graph has an embedding on a closed orientable surface with no dual loop. We associate each cubic…

Combinatorics · Mathematics 2013-10-22 Andrea Jiménez , Martin Loebl

A directed cycle double cover of a graph G is a family of cycles of G, each provided with an orientation, such that every edge of G is covered by exactly two oppositely directed cycles. Explicit obstacles to the existence of a directed…

Combinatorics · Mathematics 2014-12-02 Andrea Jiménez , Martin Loebl

A cycle cover of a bridgeless graph $G$ is a collection of simple cycles in $G$ such that each edge $e$ appears on at least one cycle. The common objective in cycle cover computation is to minimize the total lengths of all cycles. Motivated…

Distributed, Parallel, and Cluster Computing · Computer Science 2018-12-27 Merav Parter , Eylon Yogev

A circuit double cover of a bridgeless graph is a collection of even subgraphs such that every edge is contained in exactly two subgraphs of the given collection. Such a circuit double cover describes an embedding of the corresponding graph…

Combinatorics · Mathematics 2026-01-16 Meike Weiß , Reymond Akpanya , Alice C. Niemeyer

In this article, we give a positive answer to the cycle double cover conjecture. Ones who are mainly interesting in the proof of the conjecture can only read Sections 2 and 4.

Combinatorics · Mathematics 2017-12-20 Bin Shen

The problem of establishing the number of perfect matchings necessary to cover the edge-set of a cubic bridgeless graph is strictly related to a famous conjecture of Berge and Fulkerson. In this paper we prove that deciding whether this…

Combinatorics · Mathematics 2014-09-17 Louis Esperet , Giuseppe Mazzuoccolo

The cycle double cover conjecture is a long standing problem in graph theory, which links local properties, the valency of a vertex and no bridges, and a global property of the graph, being covered by a particular set of cycles. We prove…

Combinatorics · Mathematics 2025-03-05 Jens Walter Fischer

A small oriented cycle double cover (SOCDC)} of a bridgeless graph $G$ on $n$ vertices is a collection of at most $n-1$ directed cycles of the symmetric orientation, $G_s$, of $G$ such that each edge of $G_s$ lies in exactly one of the…

Combinatorics · Mathematics 2013-07-25 Behrooz Bagheri Gh. , Behnaz Omoomi
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