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A defining set of a Latin square is a partially filled-in Latin square which completes to no other Latin square of the same order. We introduce the concept of a $k$-strong defining set, in which if less than $k$ entries are deleted, the…

Combinatorics · Mathematics 2026-05-28 Richard Bean , Nicholas Cavenagh

We investigate MacNeish's conjecture (known to be false in general) in the setting of what we call "transitive" Mutually Orthogonal Latin Squares (MOLS). When we restrict our attention to "simply transitive" MOLS, we find that the…

Combinatorics · Mathematics 2026-02-02 Amadou Keita , Ilya Shapiro

In this paper we discuss dilaton shifts (Euler counterterms) arising in decomposition of two-dimensional quantum field theories with higher-form symmetries. These take a universal form, reflecting underlying (noninvertible, quantum)…

High Energy Physics - Theory · Physics 2024-10-02 E. Sharpe

Let $P$ be a partial latin square of prime order $p>7$ consisting of three cyclically generated transversals. Specifically, let $P$ be a partial latin square of the form: \[ P=\{(i,c+i,s+i),(i,c'+i,s'+i),(i,c''+i,s''+i)\mid 0 \leq i< p\} \]…

Combinatorics · Mathematics 2007-12-04 Nicholas J. Cavenagh , Carlo Hamalainen , Adrian M. Nelson

A \emph{Latin square} is a matrix of symbols such that each symbol occurs exactly once in each row and column. A Latin square $L$ is \emph{row-Hamiltonian} if the permutation induced by each pair of distinct rows of $L$ is a full cycle…

Combinatorics · Mathematics 2023-12-21 Jack Allsop , Ian M. Wanless

Haj\'os conjecture asserts that a simple Eulerian graph on n vertices can be decomposed into at most (n - 1)/2 cycles. The conjecture is only proved for graph classes in which every element contains vertices of degree 2 or 4. We develop new…

Combinatorics · Mathematics 2017-08-11 Elke Fuchs , Laura Gellert , Irene Heinrich

It is established that the logarithm of the number of latin $d$-cubes of order $n$ is $\Theta(n^{d}\ln n)$ and the logarithm of the number of pairs of orthogonal latin squares of order $n$ is $\Theta(n^2\ln n)$. Similar estimations are…

Combinatorics · Mathematics 2018-04-27 Vladimir N. Potapov

Translated from the Latin original, "Observationes circa bina biquadrata quorum summam in duo alia biquadrata resolvere liceat" (1772). E428 in the Enestroem index. This paper is about finding A,B,C,D such that $A^4+B^4=C^4+D^4$. In sect.…

History and Overview · Mathematics 2009-08-10 Leonhard Euler , Jordan Bell

Two Latin squares $L=[l(i,j)]$ and $M=[m(i,j)]$, of even order $n$ with entries $\{0,1,2,\ldots,n-1\}$, are said to be nearly orthogonal if the superimposition of $L$ on $M$ yields an $n\times n$ array $A=[(l(i,j),m(i,j))]$ in which each…

Combinatorics · Mathematics 2014-01-31 Fatih Demirkale , Diane Donovan , Abdollah Khodkar

We suggest and explore a matroidal version of the Brualdi - Ryser conjecture about Latin squares. We prove that any $n\times n$ matrix, whose rows and columns are bases of a matroid, has an independent partial transversal of length…

Combinatorics · Mathematics 2012-04-25 Daniel Kotlar , Ran Ziv

We show that for any n divisible by 3, almost all order-n Steiner triple systems have a perfect matching (also known as a parallel class or resolution class). In fact, we prove a general upper bound on the number of perfect matchings in a…

Combinatorics · Mathematics 2020-07-29 Matthew Kwan

We study random packings of $2\times2$ squares with centers on the square lattice $\mathbb{Z}^{2}$, in which the probability of a packing is proportional to $\lambda$ to the number of squares. We prove that for large $\lambda$, typical…

Mathematical Physics · Physics 2026-02-19 Daniel Hadas , Ron Peled

Given a partition $h_1+h_2+\dots+h_k = n$, a latin square of order $n$ with pairwise disjoint subsquares of orders $h_1,\dots ,h_k$ is called a realization. When the values $h_i$ are of at most two sizes, the existence of a realization has…

Combinatorics · Mathematics 2026-03-26 Tara Kemp , James G. Lefevre

Two perpendicular segments which divide a given triangle into 4 regions of equal area is called a quadrisection of the triangle. Leonhard Euler proved in 1779 that every scalene triangle has a quadrisection with its triangular part on the…

History and Overview · Mathematics 2016-11-22 Carl Eberhart

To get another from a given latin square, we have to change at least 4 entries. We show how to find these entries and how to change them.

Combinatorics · Mathematics 2019-02-18 I. I. Deriyenko

Two prominent conjectures by Herbert J. Ryser have been falsely attributed to a somewhat obscure conference proceedings that he wrote in German. Here we provide a translation of that paper and try to correct the historical record at least…

Combinatorics · Mathematics 2018-01-10 Darcy Best , Ian M. Wanless

A hypergraph is \textit{bipartite with bipartition $(A, B)$} if every edge has exactly one vertex in $A$, and a matching in such a hypergraph is \textit{$A$-perfect} if it saturates every vertex in $A$. We prove an upper bound on the number…

Combinatorics · Mathematics 2026-05-21 Tantan Dai , Alexander Divoux , Tom Kelly

O. H. Keller conjectured in 1930 that in any tiling of $\Bbb R^n$ by unit $n$-cubes there exist two of them having a complete facet in common. O. Perron proved this conjecture for $n\le 6$. We show that for all $n\ge 10$ there exists a…

Metric Geometry · Mathematics 2016-09-06 Jeffrey C. Lagarias , Peter W. Shor

E394 in the Enestrom index. Translated from the Latin original, "De partitione numerorum in partes tam numero quam specie datas" (1768). Euler finds a lot of recurrence formulas for the number of partitions of $N$ into $n$ parts from some…

History and Overview · Mathematics 2007-12-04 Leonhard Euler

A Latin hypercuboid of order $n$ is a $d$-dimensional matrix of dimensions $n\times n\times\cdots\times n\times k$, with symbols from a set of cardinality $n$ such that each symbol occurs at most once in each axis-parallel line. If $k=n$…

Combinatorics · Mathematics 2025-02-14 Candida Bowtell , Alice Devillers , André Kündgen , Padraig Ó Catháin , Ian M. Wanless
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