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A Latin square of side n defines in a natural way a finite geometry on 3n points, with three lines of size n and n^2 lines of size 3. A Latin square of side n with a transversal similarly defines a finite geometry on 3n+1 points, with three…

Combinatorics · Mathematics 2011-08-26 Lou M. Pretorius , Konrad J. Swanepoel

To get another from a given latin square, we have to change at least 4 entries. We show how to find these entries and how to change them.

Combinatorics · Mathematics 2019-02-18 I. I. Deriyenko

We show that a pair of orthogonal partial latin squares of order $n$ can be embedded in a pair of orthogonal latin squares of order at most $16n^4$ and all orders greater than or equal to $48n^4$. This paper provides the first direct…

Combinatorics · Mathematics 2014-01-24 D. Donovan , E. Ş. Yazıcı

Let $P$ be a partial latin square of prime order $p>7$ consisting of three cyclically generated transversals. Specifically, let $P$ be a partial latin square of the form: \[ P=\{(i,c+i,s+i),(i,c'+i,s'+i),(i,c''+i,s''+i)\mid 0 \leq i< p\} \]…

Combinatorics · Mathematics 2007-12-04 Nicholas J. Cavenagh , Carlo Hamalainen , Adrian M. Nelson

For $\mu$ given latin squares of order $n$, they have {\sf $k$ intersection} when they have $k$ identical cells and $n^2-k$ cells with mutually different entries. For each $n\geq 1$ the set of integers $k$ such that there exist $\mu$ latin…

Combinatorics · Mathematics 2015-09-17 P. Adams , E. S. Mahmoodian , H. Minooei , M. Mohammadi Nevisi

Let $T(n)$ denote the maximal number of transversals in an order-$n$ Latin square. Improving on the bounds obtained by McKay et al., Taranenko recently proved that $T(n) \leq \left((1+o(1))\frac{n}{e^2}\right)^{n}$, and conjectured that…

Combinatorics · Mathematics 2015-06-03 Roman Glebov , Zur Luria

A quantum Latin square of order $n$ (denoted as QLS$(n)$) is an $n\times n$ array whose entries are unit column vectors from the $n$-dimensional Hilbert space $\mathcal{H}_n$, such that each row and column forms an orthonormal basis. Two…

Quantum Physics · Physics 2026-01-15 Ying Zhang , Lijun Ji

In this note, we study large deviations of the number $\mathbf{N}$ of intercalates ($2\times2$ combinatorial subsquares which are themselves Latin squares) in a random $n\times n$ Latin square. In particular, for constant $\delta>0$ we…

Combinatorics · Mathematics 2021-12-23 Matthew Kwan , Ashwin Sah , Mehtaab Sawhney

In this paper we propose an algorithm for enumerating diagonal Latin squares of small order. It relies on specific properties of diagonal Latin squares to employ symmetry breaking techniques, and on several heuristic optimizations and bit…

Combinatorics · Mathematics 2017-09-11 Stepan Kochemazov , Eduard Vatutin , Oleg Zaikin

An arrangement of s elements in s rows and s columns, such that no element repeats more than once in each row and each column is called a Latin square of order s. If two Latin squares of the same order superimposed one on the other and in…

Discrete Mathematics · Computer Science 2011-11-09 R. N. Mohan , Moon Ho Lee , Subash Pokreal

For every positive integer $n$ greater than $4$ there is a set of Latin squares of order $n$ such that every permutation of the numbers $1,\ldots,n$ appears exactly once as a row, a column, a reverse row or a reverse column of one of the…

Combinatorics · Mathematics 2020-06-11 Stephan Foldes , András Kaszanyitzky , Laszlo Major

Gy\'{a}rf\'{a}s and S\'{a}rk\"{o}zy conjectured that every $n\times n$ Latin square has a `cycle-free' partial transversal of size $n-2$. We confirm this conjecture in a strong sense for almost all Latin squares, by showing that as $n…

Combinatorics · Mathematics 2022-04-12 Stephen Gould , Tom Kelly

Latin squares are interesting combinatorial objects with many applications. When working with Latin squares, one is sometimes led to deal with partial Latin squares, a generalization of Latin squares. One of the problems regarding partial…

Combinatorics · Mathematics 2014-03-20 Masood Aryapoor

Let $L(n)$ be the number of Latin squares of order $n$, and let $L^{\textrm{even}}(n)$ and $L^{\textrm{odd}}(n)$ be the number of even and odd such squares, so that $L(n) = L^{\textrm{even}}(n) + L^{\textrm{odd}}(n)$. The Alon-Tarsi…

Combinatorics · Mathematics 2014-12-25 Levent Alpoge

Let $m \leq n \leq k$. An $m \times n \times k$ 0-1 array is a Latin box if it contains exactly $mn$ ones, and has at most one $1$ in each line. As a special case, Latin boxes in which $m = n = k$ are equivalent to Latin squares. Let…

Combinatorics · Mathematics 2019-02-12 Zur Luria , Michael Simkin

In a Latin square, every row can be interpreted as a permutation, and therefore has a parity (even or odd). We prove that in a uniformly random $n\times n$ Latin square, the $n$ row parities are very well approximated by a sequence of $n$…

Probability · Mathematics 2025-09-19 Matthew Kwan , Kalina Petrova , Mehtaab Sawhney

Two Latin squares of order $n$ are $r$-orthogonal if, when superimposed, there are exactly $r$ distinct ordered pairs. The spectrum of all values of $r$ for Latin squares of order $n$ is known. A Latin square $A$ of order $n$ is…

Discrete Mathematics · Computer Science 2024-02-15 Sergey Bereg

A defining set of a Latin square is a partially filled-in Latin square which completes to no other Latin square of the same order. We introduce the concept of a $k$-strong defining set, in which if less than $k$ entries are deleted, the…

Combinatorics · Mathematics 2026-05-28 Richard Bean , Nicholas Cavenagh

Given an integer partition $P = (h_1h_2\dots h_k)$ of $n$, a realization of $P$ is a latin square with disjoint subsquares of orders $h_1,h_2,\dots,h_k$. Most known results restrict either $k$ or the number of different integers in $P$.…

Combinatorics · Mathematics 2025-10-02 Tara Kemp , James G. Lefevre

We say that a diagonal in an array is {\em $\lambda$-balanced} if each entry occurs $\lambda$ times. Let $L$ be a frequency square of type $F(n;\lambda^m)$; that is, an $n\times n$ array in which each entry from $\{1,2,\dots ,m\}$ occurs…

Combinatorics · Mathematics 2018-02-06 Nicholas Cavenagh , Adam Mammoliti