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For every positive integer $n$ greater than $4$ there is a set of Latin squares of order $n$ such that every permutation of the numbers $1,\ldots,n$ appears exactly once as a row, a column, a reverse row or a reverse column of one of the…

Combinatorics · Mathematics 2020-06-11 Stephan Foldes , András Kaszanyitzky , Laszlo Major

Given an $n\times n$ array $M$ ($n\ge 7$), where each cell is colored in one of two colors, we give a necessary and sufficient condition for the existence of a partition of $M$ into $n$ diagonals, each containing at least one cell of each…

Combinatorics · Mathematics 2015-08-18 Dani Kotlar , Ran Ziv

A $k$-plex in a latin square of order $n$ is a selection of $kn$ entries that includes $k$ representatives from each row and column and $k$ occurrences of each symbol. A $1$-plex is also known as a transversal. It is well known that if $n$…

Combinatorics · Mathematics 2018-01-10 Nicholas J. Cavenagh , Ian M. Wanless

Two latin squares are orthogonal if, when they are superimposed, every ordered pair of symbols appears exactly once. This definition extends naturally to `incomplete' latin squares each having a hole on the same rows, columns, and symbols.…

Combinatorics · Mathematics 2014-10-27 Peter J. Dukes , Christopher M. van Bommel

We show that a pair of orthogonal partial latin squares of order $n$ can be embedded in a pair of orthogonal latin squares of order at most $16n^4$ and all orders greater than or equal to $48n^4$. This paper provides the first direct…

Combinatorics · Mathematics 2014-01-24 D. Donovan , E. Ş. Yazıcı

We show that any partial Latin square of order $n$ can be embedded in a Latin square of order at most $16n^2$ which has at least $2n$ mutually orthogonal mates. We also show that for any $t\geq 2$, a pair of orthogonal partial Latin squares…

Combinatorics · Mathematics 2018-11-13 Diane M. Donovan , Mike Grannell , Emine Şule Yazıcı

A Latin square is reduced if its first row and column are in natural order. For Latin squares of a particular order $n$ there are four possible different parities. We confirm a conjecture of Stones and Wanless by showing asymptotic equality…

Combinatorics · Mathematics 2016-10-21 Nicholas J. Cavenagh , Ian M. Wanless

A Latin square of order $n$ is an $n\times n$ array which contains $n$ distinct symbols exactly once in each row and column. We define the adjacent distance between two adjacent cells (containing integers) to be their difference modulo $n$,…

Combinatorics · Mathematics 2021-07-19 Omar Aceval , Paige Beidelman , Jieqi Di , James Hammer , Mitchel O'Connor , Caitlin Owens , Yewen Sun

It is known that $N(n)$, the maximum number of mutually orthogonal latin squares of order $n$, satisfies the lower bound $N(n) \ge n^{1/14.8}$ for large $n$. For $h\ge 2$, relatively little is known about the quantity $N(h^n)$, which…

Combinatorics · Mathematics 2020-08-21 Michael Bailey , Coen del valle , Peter J. Dukes

We discuss the existence of vertex disjoint path coverings with prescribed ends for the $n$-dimensional hypercube with or without deleted vertices. Depending on the type of the set of deleted vertices and desired properties of the path…

Combinatorics · Mathematics 2013-12-09 Nelson Castañeda , Ivan S. Gotchev

Consider a partial Latin square $P$ where the first two rows and first three columns are completely filled, and every other cell of $P$ is empty. It has been conjectured that all such partial Latin squares of order at least $8$ are…

Combinatorics · Mathematics 2020-05-19 Carl Johan Casselgren , Herman Göransson

For Latin squares the units (rows and columns) have fixed sum. The same holds for rows, columns, and blocks in Sudokus. Summing the elements of a unit yields a linear equation, and the set of all such equations forms a system of linear…

General Mathematics · Mathematics 2025-09-16 Ralf Pöppel

A latin hypercuboid of order $N$ is an $N\times...\times N\times k$ array filled with symbols from the set $\{0,...,N-1\} $ in such a way that every symbol occurs at most once in every line. If $k=N$, such an array is a latin hypercube. We…

Combinatorics · Mathematics 2011-01-20 Vladimir N. Potapov

We obtain a combinatorial proof of a surprising weighted partition equality of Berkovich and Uncu. Our proof naturally leads to a formula for the number of partitions with a given parity of the smallest part, in terms of S(i), the number of…

Combinatorics · Mathematics 2022-05-13 Damanvir Singh Binner

A Latin square has six conjugate Latin squares obtained by uniformly permuting its (row, column, symbol) triples. We say that a Latin square has conjugate symmetry if at least two of its six conjugates are equal. We enumerate Latin squares…

Combinatorics · Mathematics 2021-12-09 Brendan D. McKay , Ian M. Wanless

In 1782, Euler conjectured that no Latin square of order $n\equiv 2\; \textrm{mod}\; 4$ has a decomposition into transversals. While confirmed for $n=6$ by Tarry in 1900, Bose, Parker, and Shrikhande constructed counterexamples in 1960 for…

Combinatorics · Mathematics 2025-01-10 Candida Bowtell , Richard Montgomery

Until now the problem counting Latin rectangles m x n has been solved with an explicit formula for m = 2, 3 and 4 only. In the present paper an explicit formula is provided for the calculation of the number of Latin rectangles for any order…

Combinatorics · Mathematics 2007-11-06 Aurelio de Gennaro

The Dinitz conjecture states that, for each $n$ and for every collection of $n$-element sets $S_{ij}$, an $n\times n$ partial latin square can be found with the $(i,j)$\<th entry taken from $S_{ij}$. The analogous statement for $(n-1)\times…

Combinatorics · Mathematics 2009-09-25 Jeannette C. M. Janssen

We demonstrate the existence of $K$-multimagic squares of order $N$ consisting of distinct integers whenever $N>2 K(K+1)$. This improves upon our earlier result in which we only required $N+1$ distinct integers. Additionally, we present a…

Number Theory · Mathematics 2025-01-03 Daniel Flores

We prove that for all n>1 every latin n-dimensional cube of order 5 has transversals. We find all 123 paratopy classes of layer-latin cubes of order 5 with no transversals. For each $n\geq 3$ and $q\geq 3$ we construct a (2q-2)-layer latin…

Combinatorics · Mathematics 2025-12-01 A. L. Perezhogin , V. N. Potapov , S. Yu. Vladimirov