English
Related papers

Related papers: A Wallace semigroup whose every finite power is co…

200 papers

We prove that the existence of $\mathfrak{c}$ incomparable selective ultrafilters implies the existence of a Wallace semigroup whose cube is countably compact. In addition, assuming the existence of $2^{\mathfrak c}$ incomparable selective…

General Topology · Mathematics 2022-10-19 J. L. J. Fuentes-Maguiña , A. H. Tomita

We prove that the existence of a selective ultrafilter implies the existence of a countably compact Hausdorff group topology on the free Abelian group of size continuum. As a consequence, we show that the existence of a selective…

General Topology · Mathematics 2020-06-25 A. C. Boero , I. Castro-Pereira , A. H. Tomita

We prove that if there are $\mathfrak c$ incomparable selective ultrafilters then, for every infinite cardinal $\kappa$ such that $\kappa^\omega=\kappa$, there exists a group topology on the free Abelian group of cardinality $\kappa$…

Logic · Mathematics 2021-03-25 M. K. Bellini , K. P. Hart , V. O. Rodrigues , A. H. Tomita

We construct in ZFC a countably compact group without non-trivial convergent sequences of size $2^{\mathfrak{c}}$, answering a question of Bellini, Rodrigues and Tomita. We also construct in ZFC a selectively pseudocompact group which is…

General Topology · Mathematics 2021-09-01 Artur Hideyuki Tomita , Juliane Trianon-Fraga

Assuming the existence of $\mathfrak c$ incomparable selective ultrafilters, we classify the non-torsion Abelian groups of cardinality $\mathfrak c$ that admit a countably compact group topology. We show that for each $\kappa \in [\mathfrak…

General Topology · Mathematics 2021-04-26 M. K. Bellini , A. C. Boero , V. O. Rodrigues , A. H. Tomita

A space $X$ is called {\it selectively pseudocompact} if for each sequence $(U_{n})_{n\in \mathbb{N}}$ of pairwise disjoint nonempty open subsets of $X$ there is a sequence $(x_{n})_{n\in \mathbb{N}}$ of points in $X$ such that $cl_X(\{x_n…

General Topology · Mathematics 2017-06-16 S. Garcia-Ferreira , A. H. Tomita

In 1990, Comfort asked: is there, for every cardinal number $\alpha \leq 2^{\mathfrak{c}}$, a topological group $G$ such that $G^\gamma$ is countably compact for all cardinals $\gamma<\alpha$, but $G^\alpha$ is not countably compact? A…

General Topology · Mathematics 2022-11-29 Artur Hideyuki Tomita , Juliane Trianon-Fraga

We show that if $\kappa \leq \omega$ and there exists a group topology without non-trivial convergent sequences on an Abelian group $H$ such that $H^n$ is countably compact for each $n<\kappa$ then there exists a topological group $G$ such…

General Topology · Mathematics 2020-06-25 Artur Hideyuki Tomita

We prove that, consistently with ZFC, no ultraproduct of countably infinite (or separable metric, non-compact) structures is isomorphic to a reduced product of countable (or separable metric) structures associated to the Fr\'echet filter.…

Logic · Mathematics 2022-07-18 Ilijas Farah , Saharon Shelah

We answer the question, raised more than thirty years ago, on whether the power (G raised to the power omega) of a countably compact minimal Abelian group G is minimal, by showing that the negative answer is equivalent to the existence of…

Logic · Mathematics 2021-12-17 Dikran Dikranjan , Vladimir Uspenskij

We prove that if S is a commutative semigroup with well founded universal semilattice or a solvable inverse semigroup with well founded semilattice of idempotents, then every strongly productive ultrafilter on S is idempotent. Moreover we…

Logic · Mathematics 2016-05-06 David Fernández Bretón , Martino Lupini

It is proven that if $G$ is a finite group, then $G^\omega$ has $2^{\mathfrak c}$ dense nonmeasurable subgroups. Also, other examples of compact groups with dense nonmeasurable subgroups are presented.

General Topology · Mathematics 2014-07-04 F. Javier Trigos-Arrieta

The existence of a countably compact group without non-trivial convergent sequences in ZFC alone is a major open problem in topological group theory. We give a ZFC example of a Boolean topological group G without non-trivial convergent…

General Topology · Mathematics 2018-12-27 Dmitri Shakhmatov , Víctor Hugo Yañez

A long-standing question in the theory of measures of noncompactness is that for the Kuratowski measure of noncompactness $\alpha$ defined on a metric space $M$, and for every bounded subset $B\subset M$, is there a countable subset…

Functional Analysis · Mathematics 2021-01-28 Xiaoling Chen , Lixin Cheng

We prove that consistently there is a singular cardinal $\kappa$ of uncountable cofinality such that $2^\kappa$ is weakly inaccessible, and every regular cardinal strictly between $\kappa$ and $2^\kappa$ is the character of some uniform…

Logic · Mathematics 2019-07-30 James Cummings , Charles Morgan

In 1981/82, Hickin \& Plotkin and McKenzie both proved that a finite group has only countably many non-isomorphic subdirect powers if and only if it is abelian. In this paper, we prove that a finite commutative semigroup has only countably…

Group Theory · Mathematics 2022-09-01 Ashley Clayton , Nik Ruskuc

We prove from suitable large cardinal hypotheses that the least weakly compact cardinal can be unfoldable, weakly measurable and even nearly $\theta$-supercompact, for any desired $\theta$. In addition, we prove several global results…

Logic · Mathematics 2013-05-28 Brent Cody , Moti Gitik , Joel David Hamkins , Jason Schanker

Homogeneous countably compact spaces $X$ and $Y$ whose product $X\times Y$ is not pseudocompact are constructed. It is proved that all compact subsets of homogeneous subspaces of the third power of an extremally disconnected space are…

General Topology · Mathematics 2023-06-13 Evgenii Reznichenko

It is proved that the existence of a countable extremally disconnected Boolean topological group containing a family of open subgroups whose intersection has empty interior implies the existence of a rapid ultrafilter.

General Topology · Mathematics 2014-05-27 Ol'ga Sipacheva

We give a description of finite semigroups $S$ that are minimal for not being Malcev nilpotent, i.e. every proper subsemigroup and every proper Rees factor semigroup is Malcev nilpotent but $S$ is not. For groups this question was…

Group Theory · Mathematics 2014-07-02 E. Jespers , M. H. Shahzamanian
‹ Prev 1 2 3 10 Next ›