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Related papers: Topologically and rationally slice knots

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A knot in $S^3$ is rationally slice if it bounds a disk in a rational homology ball. We give an infinite family of rationally slice knots that are linearly independent in the knot concordance group. In particular, our examples are all…

Geometric Topology · Mathematics 2023-02-01 Jennifer Hom , Sungkyung Kang , JungHwan Park , Matthew Stoffregen

We prove that there exist infinitely many topologically slice knots which cannot bound a smooth null-homologous disk in any definite 4-manifold. Furthermore, we show that we can take such knots so that they are linearly independent in the…

Geometric Topology · Mathematics 2018-03-16 Kouki Sato

We construct an infinite family of smoothly slice knots that we prove are topologically doubly slice. Using the correction terms coming from Heegaard Floer homology, we show that none of these knots is smoothly doubly slice. We use these…

Geometric Topology · Mathematics 2017-05-17 Jeffrey Meier

Kawauchi proved that every strongly negative amphichiral knot $K \subset S^3$ bounds a smoothly embedded disk in some rational homology ball $V_K$, whose construction a priori depends on $K$. We show that $V_K$ is independent of $K$ up to…

Geometric Topology · Mathematics 2022-12-27 Adam Simon Levine

We establish a number of results about smooth and topological concordance of knots in $S^1\times S^2$. The winding number of a knot in $S^1\times S^2$ is defined to be its class in $H_1(S^1\times S^2;\mathbb{Z})\cong \mathbb{Z}$. We show…

Geometric Topology · Mathematics 2020-06-11 Christopher W. Davis , Matthias Nagel , JungHwan Park , Arunima Ray

We construct infinitely many smoothly slice knots having topological slice discs that are non-approximable by smooth slice discs.

Geometric Topology · Mathematics 2025-07-08 Min Hoon Kim , Mark Powell

The existence of topologically slice knots that are of infinite order in the knot concordance group followed from Freedman's work on topological surgery and Donaldson's gauge theoretic approach to 4-manifolds. Here, as an application of…

Geometric Topology · Mathematics 2016-09-15 Matthew Hedden , Se-Goo Kim , Charles Livingston

A knot is said to be slice if it bounds a smooth properly embedded disk in the 4-ball. We demonstrate that the Conway knot, 11n34 in the Rolfsen tables, is not slice. This completes the classification of slice knots under 13 crossings, and…

Geometric Topology · Mathematics 2018-08-10 Lisa Piccirillo

We study the $\mathbb{CP}^2$-slicing number of knots, i.e. the smallest $m\geq 0$ such that a knot $K\subseteq S^3$ bounds a properly embedded, null-homologous disk in a punctured connected sum $(\#^m\mathbb{CP}^2)^{\times}$. We give a…

Geometric Topology · Mathematics 2025-04-08 Alexandra Kjuchukova , Allison N. Miller , Arunima Ray , Sümeyra Sakallı

Hom and Wu introduced the knot concordance invariant $\nu^{+}$ for knots in $S^{3}$ and proved that it gives a lower bound for the slice genus. Wu and Yang extended $\nu^{+}$ to knots in rational homology $3$-spheres, where it gives a lower…

Geometric Topology · Mathematics 2026-03-20 Junghwan Park , Zhongtao Wu , Jingling Yang

In this paper we study rational real algebraic knots in $\R P^3$. We show that two real algebraic knots of degree $\leq5$ are rigidly isotopic if and only if their degrees and encomplexed writhes are equal. We also show that any irreducible…

Geometric Topology · Mathematics 2011-08-08 Johan Björklund

A knot K in the 3-sphere is superslice if there is a slice disk D in the 4-ball such that the double of D along K is the unknotted 2-sphere S in $S^4$. Answering a question of Livingston-Meier, we find smoothly slice (in fact doubly slice)…

Geometric Topology · Mathematics 2016-10-14 Daniel Ruberman

There are 352.2 million prime knots in the 3-sphere with at most 19 crossings. We study which of these knots are slice, in both the smooth and topological categories. While no algorithm is known for deciding whether a given knot is slice in…

Geometric Topology · Mathematics 2025-12-29 Nathan M. Dunfield , Sherry Gong

We give a complete characterization of the topological slice status of odd 3-strand pretzel knots, proving that an odd 3-strand pretzel knot is topologically slice if and only if either it is ribbon or has trivial Alexander polynomial. (By…

Geometric Topology · Mathematics 2018-03-16 Allison N. Miller

A crucial step in the surgery-theoretic program to classify smooth manifolds is that of representing a middle--dimensional homology class by a smoothly embedded sphere. This step fails even for the simple 4-manifolds obtained from the…

Geometric Topology · Mathematics 2017-07-20 Tim D. Cochran , Arunima Ray

In the early 1980's Mike Freedman showed that all knots with trivial Alexander polynomial are topologically slice (with fundamental group Z). This paper contains the first new examples of topologically slice knots. In fact, we give a…

Geometric Topology · Mathematics 2014-11-26 Stefan Friedl , Peter Teichner

We prove that there are infinitely many $(1,1)$-knots which are topologically slice, but not smoothly slice, which was a conjecture proposed by B\'ela Andr\'as R\'acz.

Geometric Topology · Mathematics 2019-01-24 Zipei Nie

We address primary decomposition conjectures for knot concordance groups, which predict direct sum decompositions into primary parts. We show that the smooth concordance group of topologically slice knots has a large subgroup for which the…

Geometric Topology · Mathematics 2021-07-01 Jae Choon Cha

As proved by Hedden and Ording, there exist knots for which the Ozsvath-Szabo and Rasmussen smooth concordance invariants, tau and s, differ. The Hedden-Ording examples have nontrivial Alexander polynomials and are not topologically slice.…

Geometric Topology · Mathematics 2008-10-18 Charles Livingston

We propose and analyze a structure with which to organize the difference between a knot in the 3-sphere bounding a topologically embedded 2-disk in the 4-ball and it bounding a smoothly embedded disk. The n-solvable filtration of the…

Geometric Topology · Mathematics 2014-11-11 Tim D. Cochran , Shelly Harvey , Peter Horn
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