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In this article, we study (102,000)-avoiding inversion sequences with a fixed number of distinct elements. By introducing simple H-paths, we derive the trivariate generating function for these inversion sequences with respect to their…

Combinatorics · Mathematics 2025-11-11 Sangwook Kim , Seunghyun Seo , Heesung Shin

We consider Problem 6.94 posed in the book Concrete Mathematics by Graham, Knuth, and Patashnik, and solve it by using bivariate exponential generating functions. The family of recurrence relations considered in the problem contains many…

Combinatorics · Mathematics 2014-03-21 J. Fernando Barbero G. , Jesús Salas , Eduardo J. S. Villaseñor

In their study of cyclic pattern containment, Domagalski et al. conjecture differential equations for the generating functions of circular permutations avoiding consecutive patterns of length 3. In this note, we prove and significantly…

Combinatorics · Mathematics 2021-07-13 Sergi Elizalde , Bruce Sagan

In this paper, we compute the distributions of the statistic number of crossings over permutations avoiding one of the pairs $\{321,231\}$, $\{123,132\}$ and $\{123,213\}$. The obtained results are new combinatorial interpretations of two…

Combinatorics · Mathematics 2021-05-18 Paul M. Rakotomamonjy , Sandrataniaina R. Andriantsoa , Arthur Randrianarivony

This paper introduces new methods based on exponential families for modeling the correlations between words in text and speech. While previous work assumed the effects of word co-occurrence statistics to be constant over a window of several…

cmp-lg · Computer Science 2008-02-03 Doug Beeferman , Adam Berger , John Lafferty

We study a recursion that generates real sequences depending on a parameter $x$. Given a negative $x$ the growth of the sequence is very difficult to estimate due to canceling terms. We reduce the study of the recursion to a problem about a…

Combinatorics · Mathematics 2010-06-08 Magnus Aspenberg , Rodrigo Perez

A permutation whose any prefix has no more descents than ascents is called a ballot permutation. In this paper, we present a decomposition of ballot permutations that enables us to construct a bijection between ballot permutations and odd…

Combinatorics · Mathematics 2021-03-09 Zhicong Lin , David G. L. Wang , Tongyuan Zhao

The $p$-th power of the logarithm of the Catalan generating function is computed using the Stirling cycle numbers. Instead of Stirling numbers, one may write this generating function in terms of higher order harmonic numbers.

Combinatorics · Mathematics 2019-01-01 Helmut Prodinger

We introduce the theory of normal ordered grammars, which gives a natural generalization of the normal ordering problem. To illustrate the main idea, we explore normal ordered grammars associated with the Eulerian polynomials and the…

Combinatorics · Mathematics 2024-04-24 Shi-Mei Ma , Toufik Mansour , Jean Yeh , Yeong-Nan Yeh

We obtain the generating functions for partial matchings avoiding neighbor alignments and for partial matchings avoiding neighbor alignments and left nestings. We show that there is a bijection between partial matchings avoiding three…

Combinatorics · Mathematics 2010-09-24 William Y. C. Chen , Neil J. Y. Fan , Alina F. Y. Zhao

An ascent sequence is one consisting of non-negative integers in which the size of each letter is restricted by the number of ascents preceding it in the sequence. Ascent sequences have recently been shown to be related to (2+2)-free posets…

Combinatorics · Mathematics 2012-07-17 Toufik Mansour , Mark Shattuck

Let $c=(C_n)_{n\ge 0}$ be the Catalan sequence and $T$ a linear and bounded operator on a Banach space $X$ such $4T$ is a power-bounded operator. The Catalan generating function is defined by the following Taylor series, $$…

Functional Analysis · Mathematics 2024-01-31 Pedro J. Miana , Natalia Romero

A new class of alternating convolutions concerning binomial coefficients and Catalan numbers are evaluated in closed forms.

Classical Analysis and ODEs · Mathematics 2021-03-09 Wenchang Chu

We study the distribution and the popularity of some patterns in $k$-ary faro words, i.e. words over the alphabet $\{1, 2, \ldots, k\}$ obtained by interlacing the letters of two nondecreasing words of lengths differing by at most one. We…

Combinatorics · Mathematics 2021-05-19 Jean-Luc Baril , Alexander Burstein , Sergey Kirgizov

The Catalan numbers (C_n)_{n >= 0} = 1,1,2,5,14,42,... form one of the most venerable sequences in combinatorics. They have many combinatorial interpretations, from counting bracketings of products in non-associative algebra to counting…

Combinatorics · Mathematics 2021-02-11 Paul E. Gunnells

The notion of a mesh pattern was introduced recently, but it has already proved to be a useful tool for description purposes related to sets of permutations. In this paper we study eight mesh patterns of small lengths. In particular, we…

Combinatorics · Mathematics 2012-10-01 Sergey Kitaev , Jeffrey Liese

In this paper, we compute and demonstrate the equivalence of the joint distribution of the first letter and descent statistics on six avoidance classes of permutations corresponding to two patterns of length four. This distribution is in…

Combinatorics · Mathematics 2021-05-19 Toufik Mansour , Mark Shattuck

This paper considers the enumeration of trees avoiding a contiguous pattern. We provide an algorithm for computing the generating function that counts n-leaf binary trees avoiding a given binary tree pattern t. Equipped with this counting…

Combinatorics · Mathematics 2015-03-13 Eric S. Rowland

We have extended classical pattern avoidance to a new structure: multiple task-precedence posets whose Hasse diagrams have three levels, which we will call diamonds. The vertices of each diamond are assigned labels which are compatible with…

Combinatorics · Mathematics 2023-06-22 Mitchell Paukner , Lucy Pepin , Manda Riehl , Jarred Wieser

Catalan numbers $C(n)=\frac{1}{n+1}{2n\choose n}$ enumerate binary trees and Dyck paths. The distribution of paths with respect to their number $k$ of factors is given by ballot numbers $B(n,k)=\frac{n-k}{n+k}{n+k\choose n}$. These integers…

Combinatorics · Mathematics 2008-11-03 Jean-Christophe Aval
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