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It is known that $\sum\limits_{i =1}^\infty {1/ i^2}={\pi^2/6}$. Meir and Moser asked what is the smallest $\epsilon$ such that all the squares of sides of length $1$, $1/2$, $1/3$, $\ldots$ can be packed into a rectangle of area…

Combinatorics · Mathematics 2022-12-09 Antal Joós

In this paper, we prove that for any $1/2<t<1$, there exists a positive integer $N_{0}$ depending on $t$ such that for any $n_{0}\geq N_{0}$, squares of sidelength $f(n)^{-t}$ for $n\geq n_{0}$ can be packed with disjoint interiors into a…

Metric Geometry · Mathematics 2022-10-20 Keiju Sono

Let $d$ be an integer greater than $1$, and let $t$ be fixed such that $\frac{1}{d} < t < \frac{1}{d-1}$. We prove that for any $n_0$ chosen sufficiently large depending upon $t$, the $d$-dimensional cubes of sidelength $n^{-t}$ for $n \geq…

Metric Geometry · Mathematics 2023-02-20 Rory McClenagan

Moser asked whether the collection of rectangles of dimensions 1 x 1/2, 1/2 x 1/3, 1/3 x 1/4, ..., whose total area equals 1, can be packed into the unit square without overlap, and whether the collection of squares of side lengths 1/2,…

Metric Geometry · Mathematics 2007-05-23 Greg Martin

It is known that $\sum\limits_{i=1}^{\infty} \frac{1}{i (i+1)} = 1$. In 1968, Meir and Moser asked for finding the smallest $\epsilon$ such that all the rectangles of sizes $1/i \times 1/(i + 1)$ for $i = 1, 2, \ldots$, can be packed into a…

Combinatorics · Mathematics 2022-11-21 Mingliang Zhu , Antal Joós

The problem widely known as Moser's Square Packing Problem asks for the smallest area $A$ such that for any set $S$ of squares of total area $1$, there exists a rectangle $R$ of area $A$ into which the squares in $S$ permit an…

Computational Geometry · Computer Science 2021-03-12 Meike Neuwohner

The well-known problem stated by A. Meir and L. Moser consists in tiling the unit square with rectangles (details), whose side lengths equal $1/n\times 1/(n+1)$, where indices~$n$ range from 1 to infinity. Recently, Terence Tao has proved…

Combinatorics · Mathematics 2025-07-24 A. D. Kislovskiy , E. Yu. Lerner , I. A. Senkevich

We show that a large square of sidelength $x$ can be packed by unit squares in a manner so that the wasted space $W(x) = O(x^{3/5})$.

Algebraic Geometry · Mathematics 2026-02-03 Rory McClenagan

The Mondrian problem consists of dissecting a square of side length $n\in \NN$ into non-congruent rectangles with natural length sides such that the difference $d(n)$ between the largest and the smallest areas of the rectangles partitioning…

Combinatorics · Mathematics 2020-07-21 C. Dalfó , M. A. Fiol , N. López

Given a point set $S=\{s_1,\ldots , s_n\}$ in the unit square $U=[0,1]^2$, an anchored square packing is a set of $n$ interior-disjoint empty squares in $U$ such that $s_i$ is a corner of the $i$th square. The reach $R(S)$ of $S$ is the set…

Computational Geometry · Computer Science 2018-06-26 Hugo A. Akitaya , Matthew D. Jones , David Stalfa , Csaba D. Tóth

Let $S$ be a set of $n$ points in the unit square $[0,1]^2$, one of which is the origin. We construct $n$ pairwise interior-disjoint axis-aligned empty rectangles such that the lower left corner of each rectangle is a point in $S$, and the…

Combinatorics · Mathematics 2012-07-31 Adrian Dumitrescu , Csaba D. Tóth

In their 2009 note: \emph{Packing equal squares into a large square}, Chung and Graham proved that the uncovered area of a large square of side length $x$ is $O\left(x^{(3+\sqrt{2})/7}\log x\right)$ after maximum number of non-overlapping…

Combinatorics · Mathematics 2016-04-12 Shuang Wang , Tian Dong , Jiamin Li

Let $f(n)$ denote the maximum sum of the side lengths of $n$ non-overlapping squares packed inside a unit square. We prove that $f(n^2+1) = n$ for all positive integers $n$ if and only if the sum $\sum_{k\geq 1}(f(k^2+1)-k)$ converges. We…

Combinatorics · Mathematics 2025-12-23 Anshul Raj Singh

Let $f(n)$ denote the maximum total length of the sides of $n$ squares packed inside a unit square. Erd\H{o}s conjectured that $f(k^2+1)=k$. We show that the conjecture is true if we assume that the sides of the squares are parallel to the…

Combinatorics · Mathematics 2024-11-19 Jineon Baek , Junnosuke Koizumi , Takahiro Ueoro

We show that deciding whether a given set of circles can be packed into a rectangle, an equilateral triangle, or a unit square are NP-hard problems, settling the complexity of these natural packing problems. On the positive side, we show…

Computational Geometry · Computer Science 2010-09-21 Erik D. Demaine , Sandor P. Fekete , Robert J. Lang

We provide a tight result for a fundamental problem arising from packing squares into a circular container: The critical density of packing squares into a disk is $\delta=\frac{8}{5\pi}\approx 0.509$. This implies that any set of (not…

Computational Geometry · Computer Science 2022-03-30 Sándor P. Fekete , Vijaykrishna Gurunathan , Kushagra Juneja , Phillip Keldenich , Linda Kleist , Christian Scheffer

In 1967, Moon and Moser proved a tight bound on the critical density of squares in squares: any set of squares with a total area of at most 1/2 can be packed into a unit square, which is tight. The proof requires full knowledge of the set,…

Discrete Mathematics · Computer Science 2017-01-03 Sándor P. Fekete , Hella-Franziska Hoffmann

We prove that one can cover the $1 \times b$ rectangle by equal squares on both sides in one layer iff $b = p \pm \sqrt{p^2 - r^2} $, where $p \ge r \ge 0$ and $p,q \in \mathbb{Q}$.

Combinatorics · Mathematics 2020-09-17 Fedor Ozhegov

In this paper we have a look at squared squares with small integer sidelengths, where the only restriction is that any two subsquares of the same size are not allowed to share a full border. We prove that there are exactly two such squared…

Combinatorics · Mathematics 2013-07-10 Lorenz Milla

In mathematics, a dissection of a square (or rectangle) into non-congruent rectangles is a Mondrian partition. If all the rectangles have the same area, it is called a perfect Mondrian partition. In this paper, we present a computational…

Combinatorics · Mathematics 2023-11-07 Natalia García-Colín , Dimitri Leemans , Mia Müßig , Érika Roldán
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